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zhannawk [14.2K]
3 years ago
14

Solve equation by using the quadratic formula. 15x^2 + 13x = 0

Mathematics
1 answer:
MariettaO [177]3 years ago
3 0

Answer:

0 and - 13/15

Step-by-step explanation:

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Write 14/5<br> as a mixed number.
mylen [45]

Answer: 2 4/5

Step-by-step explanation:

4 0
4 years ago
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The equation for line t can be written as y = 4x - 8. Line u, which is perpendicular to line t,
xeze [42]

Here, we are required to determine the equation of the line u which is perpendicular to the line t and passes through the point (8,8).

The equation of the line u is;. y = (-x/4) + 10.

First, the product of the slope of 2 perpendicular lines is negative 1 i.e -1.

M1 × M2 = -1

From observation, the slope of line t given by y = 4x - 8 is equal to 4.

  • Therefore, since M1 = 4,
  • Then, M2 = -1/4

To get the equation of a line,

Slope, M2 = (y - y1)/(x - x1)

where M2 = -1/4 , y1 = 8 and x1 = 8.

Therefore, -1/4 = (y - 8)/(x - 8).

Therefore, -x + 8 = 4y -32

Therefore, 4y = -x + 40.

Ultimately, the equation of the line u is ;

y = (-x/4) + 10.

Read more:

brainly.com/question/19506739

8 0
3 years ago
48 out of 60 is what<br>percent?​
vodomira [7]

Answer:

0.8 percent

Step-by-step explanation:

In order to find the answer of .8 which is equivalent to 80%, you would have to do 48 divided by 60.

6 0
3 years ago
The angle of elevation of the top of a tree from a point 100 meters from the foot of the tree is 36 degrees. How high is the tre
Veseljchak [2.6K]
To answer this question we can think Soh Cah Toa. If we are 100 ft from the tree and at an angle of 36 degrees and we want what I call the rise we can us the Toa formula tan(36)=o/100 then manipulate algebraically until we get the following o=tan(36)(100) this give us the height (o) to be 72.65 meters
7 0
3 years ago
A person 6ft tall stands 10ft from point P directly beneath a lantern hanging 30 ft above the ground. The lantern start to fall,
xxMikexx [17]

Answer:

\frac{dL}{dt}=30 \frac{ft}{s}

Step-by-step explanation:

In order to solve this it is always a good idea to start by drawing a diagram of the situation (See attached picture).

From the diagram we can see that we are dealing with similar triangles. We can use similar triangles to build an equation that relates the length of the shadow with the height of the lamp, so we get:

\frac{L}{6}=\frac{10+L}{h}

the height of the lamp can be found by subtracting the 16t^{2} distance the lamp falls in a given time t from the original 30ft the lamp was located at.

So the equation will now lok like this:

\frac{L}{6}=\frac{10+L}{30-16t^{2}}

So now we can solve the equation for L, we can start by multiplying by the LCD SO WE GET:

L(30-16t^{2})=6(10+L)

next, we can distribute the right side of the equation so we get:

L(30-16t^{2})=60+6L

and subtract 6L from both sides so we get:

L(30-16t^{2})-6L=60

and factor L, so we get:

L(30-16t^{2}-6)=60

and solve for L:

L=\frac{60}{24-16t^{2}}

now, we can differentiate this equation by using the chain rule, so we get:

dL=-\frac{60}{(24-16t^{2})^{2}}(-32t)dt

which can be simplified to:

\frac{dL}{dt}=\frac{1920t}{(24-16t^{2})^{2}}

and now we can substitute t for 1s so we get:

\frac{dL}{dt}=\frac{1920(1)}{(24-16(1)^{2})^{2}}

\frac{dL}{dt}=30 \frac{ft}{s}

7 0
3 years ago
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