• f(x) = 3x + 4
• g(x) = 8x + 1
Sum both functions above:
(f + g)(x) = f(x) + g(x)
(f + g)(x) = (3x + 4) + (8x + 1)
(f + g)(x) = 3x + 8x + 4 + 1
(f + g)(x) = 11x + 5
Therefore,
(f + g)(0) = 11 · 0 + 5
(f + g)(0) = 0 + 5
(f + g)(0) = 5 <——— this is the answer.
I hope this helps! =)
Answer:
c
Step-by-step explanation:
A perfect square trinomial is always in the form
(a+b)(a+b)= 
ie. (x+4)(x+4)= 
Answer:
B
Step-by-step explanation:
18 = 2 * 3 * 3 = 2 *3²


Hint:

Answer:
61,940
Step-by-step explanation:
For a recursive sequence of reasonable length, it is convenient to use a suitable calculator for figuring the terms of it. Since each term not only depends on previous terms, but also depends on the term number, it works well to use a spreadsheet for doing the calculations. The formula is easily entered and replicated for as many terms as may be required.
__
The result of executing the given algorithm is shown in the attachment. (We have assumed that g_1 means g[-1], and that g_2 means g[-2]. These are the starting values required to compute g[0] when k=0.
That calculation looks like ...
g[0] = (0 -1)×g[-1] +g[-2} = (-1)(9) +5 = -4
The attachment shows the last term (for k=8) is 61,940.