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padilas [110]
3 years ago
6

What are 1/4 and 1/2 opposites

Mathematics
1 answer:
nika2105 [10]3 years ago
8 0

Answer:

3/4 and 1/2

Step-by-step explanation:

1/4 is one piece out of four. if you want to make the fraction whole, you add 3. therefor, the opposite is 3/4. same thing for 1/2

You might be interested in
The vertices of ∆ABC are A(2, 8), B(16, 2), and C(6, 2). what is the perimeter and area in square units
ad-work [718]
Check the picture below.

the triangle has that base and that height, recall that A = 1/2 bh.

now as for the perimeter, you can pretty much count the units off the grid for the segment CB, so let's just find the lengths of AC and AB,

\bf ~~~~~~~~~~~~\textit{distance between 2 points}\\\\
\begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
%  (a,b)
&A&(~ 2 &,& 8~) 
%  (c,d)
&C&(~ 6 &,& 2~)
\end{array}~~~ 
%  distance value
d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}
\\\\\\
AC=\sqrt{(6-2)^2+(2-8)^2}\implies AC=\sqrt{4^2+(-6)^2}
\\\\\\
AC=\sqrt{16+36}\implies AC=\sqrt{52}\implies AC=\sqrt{4\cdot 13}
\\\\\\
AC=\sqrt{2^2\cdot 13}\implies AC=2\sqrt{13}

\bf ~~~~~~~~~~~~\textit{distance between 2 points}\\\\
\begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
%  (a,b)
&A&(~ 2 &,& 8~) 
%  (c,d)
&B&(~ 16 &,& 2~)
\end{array}\\\\\\
AB=\sqrt{(16-2)^2+(2-8)^2}\implies AB=\sqrt{14^2+(-6)^2}
\\\\\\
AB=\sqrt{196+36}\implies AB=\sqrt{232}\implies AB=\sqrt{4\cdot 58}
\\\\\\
AB=\sqrt{2^2\cdot 58}\implies AB=2\sqrt{58}

so, add AC + AB + CB, and that's the perimeter of the triangle.

8 0
3 years ago
Please help. Please. I will mark brainliest
kolbaska11 [484]

Answer:

what type of math is this i never seen this before

7 0
3 years ago
your mother gave you 14.28 with which to buy a present. this covered 3/4 of the cost. how much did the present cost?
saul85 [17]

$19.04. If your mom gave you $14.28, and it only covered 3/4 of the cost, you have to first find 3/4 as a percentage, and then put it into a decimal. It would be 0.75. So then you have to divide 14.28÷0.75. It turns out to be $19.04.

8 0
2 years ago
Can someone answer this plz (-2z^2-14)-(-12z^2)
Orlov [11]

Answer:

\large\boxed{(-2z^2-14)-(-12z^2)=10z^2-14}

Step-by-step explanation:

(-2z^2-14)-(-12z^2)=-2z^2-14+12z^2\qquad\text{combine like terms}\\\\=(-2z^2+12z^2)-14=10z^2-14

8 0
3 years ago
What is the range of the function y = x2? all real numbers x ≥ 0 y ≥ 0
masya89 [10]

Answer:

Step-by-step explanation:

Todos los reales

4 0
2 years ago
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