3 years ago

PLEASE HELP!! ILL MARK BRAINLIEST THANKS!!

Mathematics

1 answer:

Gre4nikov [31]3 years ago

7 0

Answer:

2985984

Hope this helps

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Rounded to the nearest hundredth, what is the positive solution to the quadratic equation 0 = 2x2 + 3x – 8? Quadratic formula: x

OleMash [197]

ANSWER

$x=1.39$ to the nearest hundredth.

EXPLANATION

We have the equation,

$0=2x^2+3x-8$

Which can be rewritten as

$2x^2+3x-8=0$

The question demands the use of the quadratic formula.

Comparing this to the general quadratic equation;

$ax^2+bx+c=0$

$a=2,b=3,c=-8$

The quadratic formula is given by;

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

We now substitute all the values in to the formula;

$x=\frac{-3\pm\sqrt{(3)^2-4(2)(-8)}}{2(2)}$

We simplify to obtain;

$x=\frac{-3\pm\sqrt{9+64}}{4}$

$x=\frac{-3\pm\sqrt{73}}{4}$

We now split the plus or minus sign to obtain;

$x=\frac{-3-\sqrt{73}}{4}$

This implies that;

$x=-2.89$

$x=\frac{-3+\sqrt{73}}{4}$

This will evaluate to;

$x=1.39$

Hence, the positive solution rounded to the nearest hundredth is

$x \approx 1.39$

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