PLEASE HELP!! ILL MARK BRAINLIEST THANKS!!

Is that an accurate line of best fit? A.Yes B.No I really need help !!!!!!

Cloud [144]

Answer:

yessssss

Step-by-step explanation:

hope this helps

8 0

3 years ago

Read 2 more answers

I need help with Question 14 . I need to submit it by monday... Pls help

GaryK [48]

Answer:

Distance between A and B is 5400 meters

Step-by-step explanation:

Consider "D" the letter to identify distance between A and B

Let's use "t" to identify the time of the first encounter (Devi and Kumar), and create an equation that states that the distance covered by Devi (at 100 m/min) in time "t", is equal to the total distance D minus what Kumar has covered at his speed (80 m/min) in that same time:

Recall that distance equals the speed times the time:

distance= speed * time

First encounter:

100 * t = D - 80 * t

180 * t = D Equation (1)

Not, 6 minutes later (at time t+6) , Devi and Li Ting meet .

Then for this encounter the distance covered by Devi equals total distance d minus the distance covered by Li Ting:

100 *(t+6) = D - 75 * (t+6)

100 t + 600 = D - 75 t - 450

175 T + 150 = D Equation (2)

Now, let's equal equation (1) to equation (2), since D should be the same:

180 t = 175 t + 150

5 t = 150

t = 30

Then the time t (first encounter) is 30 minutes. Knowing this, we can use either equation to find D:

From Equation (1) for example: D = 180 * t = 180 * 30 = 5400 meters

5 0

3 years ago

PLEASE HELP ME, and explain it please please please <3

ser-zykov [4K]

The answer would be f(x)= x+47

7 0

2 years ago

Two cards are drawn with replacement, one after the other, and the outcomes recorded. What is the probability that at least one

babymother [125]

Answer:

The probability is 0.231

Step-by-step explanation:

In this question, we are tasked with calculating the probability that out of two cards drawn with replacement from a pack of cards , at least one of the two is a face card.

In a standard pack of cards, there are 52 cards.

Now let’s calculate the number of face cards we have.

There are 12 face cards in a pack of cards. There are 4 of each of Jack, Queen or King

The probability of drawing a face card is 12/52 = 3/13

Now, we want to calculate the probability of at least one of the cards drawn are face cards.

Mathematically, what we are needing to calculate is

Probability of drawing a single face card or probability of the two being a face card

Now let’s calculate.

The probability of the first card drawn being a face card is 3/13. The probability of the second card not being a face card will be 1-3/13 = 10/13

The joint probability under this first set of condition will be 3/13 * 10/13 = 30/169

Now, for the second condition, here we are considering that both cards drawn are face cards. What we have is 3/13 * 3/13 = 9/169

Now in probabilities, whenever we are having the statement or, we add the probabilities together

Thus, the probability here would be 30/169 + 9/169 = 39/169 = 3/13

In decimal this will be 0.231

8 0

2 years ago

A public relations firm found that only 27% of voters in a certain state are satisfied with their U.S. senators. How large a sam

OLga [1]

Answer:

a) 38

Step-by-step explanation:

The normal distribution can be applied if:

$np \geq 5$ and $n(1-p) \geq 5$

In this question:

$p = 0.27$

Then

a) 38

n = 38.

Then

38*0.27 = 10.26

38*0.73 = 27.74

Satisfies. But is this the smallest sample of the options which satisfies.

b) 14

n = 14

Then

14*0.23 = 3.22

14*0.77 = 10.78

Does not satisfy

c) 10

Smaller than 14, which also does not satisfy, so 10 does not satisfy.

d) 48

Greater than 38, which already satisfies. So the answer is a)

8 0

3 years ago