I don’t really know what the answer is
Answer: The proof is mentioned below.
Step-by-step explanation:
Here, Δ ABC is isosceles triangle.
Therefore, AB = BC
Prove: Δ ABO ≅ Δ ACO
In Δ ABO and Δ ACO,
∠ BAO ≅ ∠ CAO ( AO bisects ∠ BAC )
∠ AOB ≅ ∠ AOC ( AO is perpendicular to BC )
BO ≅ OC ( O is the mid point of BC)
Thus, By ASA postulate of congruence,
Δ ABO ≅ Δ ACO
Therefore, By CPCTC,
∠B ≅ ∠ C
Where ∠ B and ∠ C are the base angles of Δ ABC.
So the formula to workout the area of a rectangle is height X width
so 11/3 x 5/8
which is 55/24 ft if they want a mixed number then... 2 
hope this helps
Answer:
1184.5
Step-by-step explanation:
150+400+180+300=1030
1030 × 15% = 154.5
(15% is also 0.15)
1030 + 154.5 = 1184.5
I hope this helps you :)
Answer:
Step-by-step explanation:
the perimeter of the semi-circle would be the diameter plus the circumference of half of the circle.
They want to know the perimeter of a square using the diameter of the sem-circle as ONE side, so the perimeter of the square would be 4 times the ONE side.
We should recall:
diameter = 2 times the radius circumference of a cirlce = 2π r
How do we find the diameter of the of the semi circle?
The perimeter of the semi circle is given as 108 cm
Perimeter of the semicirle = 2r + π r diameter plus semi circumference
108 = r ( 2 + π) factor out the r and solve for r
108 / (2 + π) = r divide both sides by ( 2 + r)
Now we know r, the perimeter of the squqre is 4 times 2r or 8r
perimeter of square = 8 [ 108 / (2 + π) ] π I used 3.14
= 864 / 5.14
= 168.1 cm I got rounded to nearest tenth
<em>When I re-checked by work I found a few math, logic and calculation errors. Please re-check my answer for any more mistakes.</em>
