Please help! I don’t have much to offer except the crown icon thing and 15 points.
1 answer:
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Answer:
-20x+8
Step-by-step explanation:
Step 1: rearrange the equation
16x^2 - 3x^2 - 7x - 13x +8
Step 2: solve the equation
16x^2 - 3x^2 = 13x^2
-7x - 13x = -20x
(the +8 will stay the same)
so when we put it all together it gives us
13x^2 - 20x + 8
The question is incomplete, here is the complete question:
The half-life of a certain radioactive substance is 46 days. There are 12.6 g present initially.
When will there be less than 1 g remaining?
<u>Answer:</u> The time required for a radioactive substance to remain less than 1 gram is 168.27 days.
<u>Step-by-step explanation:</u>
All radioactive decay processes follow first order reaction.
To calculate the rate constant by given half life of the reaction, we use the equation:
where,
= half life period of the reaction = 46 days
k = rate constant = ?
Putting values in above equation, we get:
The formula used to calculate the time period for a first order reaction follows:
where,
k = rate constant =
t = time period = ? days
a = initial concentration of the reactant = 12.6 g
a - x = concentration of reactant left after time 't' = 1 g
Putting values in above equation, we get:
Hence, the time required for a radioactive substance to remain less than 1 gram is 168.27 days.