Answer:
14400
Step-by-step explanation:
We have 2 groups of 5 elements each
there is a condition all boys will be ahead always, therefore in the group of boys there are
5! = 5*4*3*2*1 = 120 differents form
And the girls at the same time can change theirs places according to
5! = 120
Then total ways for the line up in the conditions of the statement of the problem are
T = 120*120
14400
Hey user
l think the answer to this is going to be
2
hope l helped u
have a good day
The number of possible selections of the five donuts is; 21
<h3>Permutation and Combination</h3>
The ample supply contains;
Since he wants to select 5 donuts, the orders could be;
Strawberry = 4, Chocolate = 1, Caramel = 0
or
Strawberry = 4, Chocolate = 0, Caramel = 1
or
Strawberry = 3, Chocolate = 2, Caramel = 0
e.t.c
Now, to solve this, Each option for Jamie is represented by an imaginary picture of five donuts (circles) and two bars (shelf separators).
Thus, the number of ways to select two spaces from 7 is;
7!/(5! × 2!) = 21
Read more about permutations and combinations at; brainly.com/question/11871015
I believe the answer is 3/14
not quite sure but thats my guess:)
√44=(√4)(√11)=2(√11)=2√11