Answer:
46.9 times
Step-by-step explanation:
First, we can calculate how many feet it takes to run around the field. To find the perimeter of a rectangle, we can use the formula
2* length + 2 * width. With the length being 450 and the width being 225 here, we can say that
2*450 + 2 * 225 = 1350 feet
Therefore, Andrew runs 1350 feet each time he runs around the field. Next, we need to figure out how much 1350 feet goes into 12 miles as we want to find how many times Andrew runs around the field to get to 12 miles. This can be represented by
12 miles/1350 feet
One thing that we can do here is multiply the fraction by 1 to keep it the same. Because 1 mile = 5280 feet, we can say that
1 mile/5280 feet = 1 = 5280 feet/1 mile. Therefore, it would be safe to multiply
12 miles/1350 feet by 1 = 5280 feet/1 mile. Note that feet is on the bottom in the first fraction (12 miles/1350 feet) and on the top in the second (5280 feet/1 mile) so they will cancel out. Similarly, miles are on top in the first and bottom in the second. We then have
12 miles/1350 feet * 5280 feet/1 mile =63360/1350 ≈ 46.9
Answer:
symmetry about the y-axis is shown
Step-by-step explanation:
Points on the right of the line of symmetry (x=0, the y-axis) are the same distance from that line as the corresponding points on the left. (That is what makes it a line of symmetry.)
There is no point of rotation that will map one figure to the other after rotation, hence no point or rotational symmetry.
Option C is answer.
Step-by-step explanation:
Hey there!
Given;

<em>Mul</em><em>tiply</em><em> </em><em>"</em><em>-</em><em>6</em><em>"</em><em> </em><em>and</em><em> </em><em>"</em><em>2</em><em>"</em><em>.</em>
<em>
</em>
<em>
</em>
<em>Shi</em><em>ft</em><em> </em><em>"</em><em>-</em><em>5</em><em>"</em><em> </em><em>on</em><em> </em><em>right</em><em> </em><em>side</em><em>.</em>
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Therefore, X = -7.
<em><u>Hope</u></em><em><u> </u></em><em><u>it</u></em><em><u> helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>
Answer:
me too
Step-by-step explanation: