Answer:
Option A is correct
The function has real zeroes at x =-10 and x =-6
Explanation:
Given: The real zeroes or roots are x = -10, and x = -6
To find the quadratic function of degree 2.
where α,β are real roots. ....[1]
Here, α= -10 and β= -6
Sum of the roots:
α+β = -10+(-6) = -10-6 = -16
Product of the roots:
αβ = (-10)(-6)= 60
Substitute these value in equation [1] we have;
Therefore, the quadratic function for the real roots at x =-10 and x =-6 ;
first one is 40 and then 65 and then 65 again
Answer:
Step-by-step explanation:
Answer: 1/4
Step-by-step explanation: i think it is 1/4 bc 48 is the total and 12 can go in 48 4 times
i hope this helped have a good day
Answer:
Step-by-step explanation:
The equation of a parabola in vertex form is
y = a(x - h)² + k
where (h, k) are the coordinates of the vertex ad a is a multiplier
Here (h, k ) = (8, - 1 ) , then
y = a(x - 8)² - 1
To find a substitute (0, - 17 ) into the equation
- 17 = a(0 - 8)² - 1 ( add 1 to both sides )
- 16 = 64a ( divide both sides by 64 )
= a , that is
a = -
y = - (x - 8)² - 1 ← equation of parabola