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shusha [124]
3 years ago
11

Helppp please !!!!!!!

Mathematics
1 answer:
borishaifa [10]3 years ago
5 0

Answer:

mentally "cut" the two different figures where they connect and find the area separately and then add them together:

4*15 = 60

11*10= 110

110+60= 170 sq mm

Step-by-step explanation:

i hope this helped :)

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\% Below\ 50 = 88 \%

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Step-by-step explanation:

Given

Total = 200

<em>The attachment presents the table properly</em>

Solving (a): Percentage of those who play for less than 50 hours weekly

To do this, we simply consider the frequency of students that fall within:

1.0 - 7.9, 8.0 - 14.9,......,43.0 - 49.9

Their frequency is:

Frequency = 21 + 37 + 40 + 27 + 23 + 18 + 10

Frequency = 176

The percentage is then calculated as:

\% Below\ 50 = \frac{Frequency}{Total} * 100\%

\% Below\ 50 = \frac{176}{200} * 100\%

\% Below\ 50 = \frac{176* 100}{200} \%

\% Below\ 50 = \frac{176* 1}{2} \%

\% Below\ 50 = \frac{176}{2} \%

\% Below\ 50 = 88 \%

Solving (b): Percentage of those who play for 43 or more hours weekly

To do this, we simply consider the frequency of students that fall within:

43.0 - 49.9,......,64.0 - 70.9

Their frequency is:

Frequency = 10 + 7 + 5+12

Frequency = 34

The percentage is then calculated as:

\% 43\ or\ more = \frac{Frequency}{Total} * 100\%

\% 43\ or\ more = \frac{34}{200} * 100\%

\% 43\ or\ more = \frac{34* 100}{200} \%

\% 43\ or\ more = \frac{34* 1}{2} \%

\% 43\ or\ more = \frac{34}{2} \%

\% 43\ or\ more = 17 \%

7 0
3 years ago
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