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4 years ago

I am so lost with this

Mathematics

2 answers:

n200080 [17]4 years ago

8 0

<span>The factors of 18 are 1, 2, 3, 6, 9, 18.</span>

lions [1.4K]4 years ago

7 0

That is all factors of 18
1 x 18
2 × 9
3 × 6

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A simple random sample of electronic components wil be selected to test for the mean lifetime in hours. Assume that component li

Serjik [45]

Answer:

189 components must be sampled.

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1 - 0.99}{2} = 0.005$

Now, we have to find z in the Ztable as such z has a pvalue of $1 - \alpha$ .

That is z with a pvalue of $1 - 0.005 = 0.995$ , so Z = 2.575.

Now, find the margin of error M as such

$M = z\frac{\sigma}{\sqrt{n}}$

Assume that component lifetimes are normally distributed with population standard deviation of 16 hours.

This means that $\sigma = 16$

How many components must be sampled so that a 99% confidence interval will have margin of error of 3 hours?

n components must be sampled.

n is found when M = 3. So

$M = z\frac{\sigma}{\sqrt{n}}$

$3 = 2.575\frac{16}{\sqrt{n}}$

$3\sqrt{n} = 2.575*16$

$\sqrt{n} = \frac{2.575*16}{3}$

$(\sqrt{n})^2 = (\frac{2.575*16}{3})^2$

$n = 188.6$

Rounding up:

189 components must be sampled.

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3 years ago

Write in slope intercept form an equation of the line<br> (1, 2); m = -2

mr Goodwill [35]

Y = 2
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2= -2 + b
+2 +2
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Answer:

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