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7nadin3 [17]
2 years ago
13

Which number sequence follows the rule multiply by 3, starting from 4?

Mathematics
2 answers:
Rom4ik [11]2 years ago
3 0

Answer:

c

Step-by-step explanation:

easy no promble at alll

jarptica [38.1K]2 years ago
3 0

Answer:

A

Step-by-step explanation:

Try mutiplying by 3 and find out.

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what multiplication expression can be broken apart into (3×4) + (3×4) using the distributive property? (1-4)
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3 x(4+4)= (3x4)+(3x4)
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2 years ago
In the situation, simple interest is calculated yearly. How much interest was earned? (Answers above)
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The simple interest formula<span> allows us to calculate I, which is the </span>interest<span> earned or charged on a loan. According to this </span>formula<span>, the amount of </span>interest<span> is given by I = Prt, where P is the principal, r is the annual </span>interest<span> rate in decimal form, and t is the loan period expressed in years.

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3 0
3 years ago
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A small box measures 4 in.by 3in. by 3/4 in. high. Find the volume of the box
GalinKa [24]

Answer:

V=e^3

Step-by-step explanation:

4 0
2 years ago
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An elevator containing five people can stop at any of seven floors. What is the probability that no two people exit at the same
elena-s [515]

Answer:

Approximately 0.15 (360 / 2401.) (Assume that the choices of the 5 passengers are independent. Also assume that the probability that a passenger chooses a particular floor is the same for all 7 floors.)

Step-by-step explanation:

If there is no requirement that no two passengers exit at the same floor, each of these 5 passenger could choose from any one of the 7 floors. There would be a total of 7 \times 7 \times 7 \times 7 \times 7 = 7^{5} unique ways for these 5\! passengers to exit the elevator.

Assume that no two passengers are allowed to exit at the same floor.

The first passenger could choose from any of the 7 floors.

However, the second passenger would not be able to choose the same floor as the first passenger. Thus, the second passenger would have to choose from only (7 - 1) = 6 floors.

Likewise, the third passenger would have to choose from only (7 - 2) = 5 floors.

Thus, under the requirement that no two passenger could exit at the same floor, there would be only (7 \times 6 \times 5 \times 4 \times 3) unique ways for these two passengers to exit the elevator.

By the assumption that the choices of the passengers are independent and uniform across the 7 floors. Each of these 7^{5} combinations would be equally likely.

Thus, the probability that the chosen combination satisfies the requirements (no two passengers exit at the same floor) would be:

\begin{aligned}\frac{(7 \times 6 \times 5 \times 4 \times 3)}{7^{5}} \approx 0.15\end{aligned}.

5 0
2 years ago
PLEASE HELP <br><br> WILL GIVE BRAINLIEST<br> AND 5.0 RATING
kipiarov [429]

Answer:

(2.5,3.5) ywww

Step-by-step explanation:

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2 years ago
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