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viva [34]
3 years ago
13

Help with this please

Mathematics
1 answer:
Scilla [17]3 years ago
8 0

Answer:

(7,4)

Step-by-step explanation:

When rotating a point 90 degrees counterclockwise about the origin our point A(x,y) becomes A'(-y,x). In other words, switch x and y and make y negative. (7,8)

Afterwards, four units down means changing the y coordinate we have, thus making our (8) into (4.)

Hope this helps!

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The mass, m grams, of a radioactive substance, present at time t days after first being observed, is given by the formula m=24e^
Reika [66]

Answer:

(i) The value of<em> m</em> when t = 30 is 13.2

(ii) The value of <em>t</em> when the mass is half of its value at t=0 is 34.7

(iii) The rate of the mass when t=50 is -0.18            

Step-by-step explanation:

(i) The <em>m</em> value when t = 30 is:

m = 24e^{-0.02t} = 24e^{-0.02*30} = 13.2

Then, the value of<em> m</em> when t = 30 is 13.2

(ii) The value of the mass when t=0 is:

m_{0} = 24e^{-0.02t} = 24e^{-0.02*0} = 24    

Now, the value of <em>t </em>is:

ln(\frac{m_{0}/2}{24}) = -0.02t

t = -\frac{ln(\frac{24}{2*24})}{0.02} = 34.7

Hence, the value of <em>t</em> when the mass is half of its value at t=0 is 34.7

(iii) Finally, the rate at which the mass is decreasing when t=50 is:

\frac{dm}{dt} = \frac{d}{dt}(24e^{-0.02t}) = 24(e^{-0.02t})*(-0.02) = -0.48*                            (e^{-0.02*50}) = -0.18

Therefore, the rate of the mass when t=50 is -0.18.

I hope it helps you!                  

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Read 2 more answers
T-4t^2+2t^3<br> Please help :(
Arada [10]

Answer:

Is there a question here?

Step-by-step explanation:

t - 4t² + 2t³ =    t(1 - 4t + 2t²)

                  =  t(2t² - 4t +1)

                  ≠≠≠≠     t(2t - 1)(t -1)

        used a graphing calculator to find the roots

       

4 0
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