What equation can be written for 29 is 6 more then k? what is K?

The population of a country has been decreasing for several decades. In 1990, the population was about 165 million people. In

Lorico [155]

To find percent decrease and increase you must subtract the original value (old value) with the new value. Then divide the value you get by the original value and multiply by 100:

165-158 = 7

7÷ 165 × 100 = 4.2424....% or 4.2% rounded to 2 significant figures.

8 0

2 years ago

a slitter assembly contains 48 blades five blades are selected at random and evaluated each day for sharpness if any dull blade

12345 [234]

Answer:

P(at least 1 dull blade)=0.7068

Step-by-step explanation:

I hope this helps.

This is what it's called dependent event probability, with the added condition that at least 1 out of 5 blades picked is dull, because from your selection of 5, you only need one defective to decide on replacing all.

So if you look at this from another perspective, you have only one event that makes it so you don't change the blades: that 5 out 5 blades picked are sharp. You also know that the probability of changing the blades plus the probability of not changing them is equal to 100%, because that involves all the events possible.

P(at least 1 dull blade out of 5)+Probability(no dull blades out of 5)=1

P(at least 1 dull blade)=1-P(no dull blades)

But the event of picking one blade is dependent of the previous picking, meaning there is no chance of picking the same blade twice.

So you have 38/48 on getting a sharp one on your first pick, then 37/47 (since you remove 1 sharp from the possibilities, and 1 from the whole lot), and so on.

Also since are consecutive events, you need to multiply the events.

The probability that the assembly is replaced the first day is:

P(at least 1 dull blade)=1-P(no dull blades)

$P(at least 1 dull blade)=1-(\frac{38}{48}* \frac{37}{47} *\frac{36}{46}*\frac{35}{45}*\frac{34}{44})$

$P(at least 1 dull blade)=1-0.2931$

P(at least 1 dull blade)=0.7068

6 0

2 years ago

If letters of the word COMPUTER are randomly arranged in a row, what is the probability that the letters CO remain next to each

Mariana [72]

The probability that the letters CO remain next to each other (in order) as a unit is $\frac{1}{8}$ .

<h3>What is probability?</h3>

The area of mathematics known as probability deals with numerical representations of the likelihood that an event will occur or that a statement is true. An event's probability is a number between 0 and 1, where, roughly speaking, 0 denotes the event's impossibility and 1 denotes certainty. It is more likely that an event will occur if its probability is higher.

When the letters are arranged randomly in a row, the total number of arrangements is 40,320 , and the number of arrangements with the letters CO next to each other (in order) as a unit is 5,040.

Therefore, possible outcomes = 5040 and

Total outcomes = 40320

Probability = $\frac{Possible outcomes}{Total outcomes}$