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Gennadij [26K]
3 years ago
14

How much larger is 10 7 than 10 3 What operation can we use?

Mathematics
1 answer:
Dmitrij [34]3 years ago
8 0

Answer:

9,999,000

subtraction

Step-by-step explanation:

We can compare numbers using subtraction or division.

A question like "how much larger" usually means a comparison by subtraction. For example, how much larger is 10 than 8. Use subtraction: 10 - 8 = 2. Answer: 2.

A question like "how many times larger" usually means a comparison by division. For example, how many times larger is 30 than 5? Use division: 30/5 = 6. Answer: 6.

Here, the question is "how much larger" not "how many times larger," so we will compare with subtraction.

10^7 - 10^3 = 10,000,000 - 1,000 = 9,999,000

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Write the equation in slope-intercept form through the point (-5, 3) and is perpendicular to the line y = 2x - 3 and graph​
xxTIMURxx [149]

Slope intercept form: y = mx + b

When a line is perpendicular to another line, its slope is the negative reciprocal to that slope.

From this information, we already know that the slope of our new line is -1/2, because -1/2 is the negative reciprocal to 2 (which is the slope of the original line).

y = -1/2x + b

Because the point (-5,3) is given, we can simply plug the x and y coordinates into our incomplete equation.

3 = -1/2(-5) + b

3=2.5 + b

b = 0.5

ANSWER: y = -1/2x + 0.5

THE GRAPH IS LINKED; RED LINE IS y=2x-3 AND BLUE LINE IS y=-1/2x + 0.5

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3 years ago
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Answer:

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6 0
3 years ago
Solve for x. <br><br> 8x/7+9=30
kodGreya [7K]
X=18 (3/8)
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3 years ago
I need help I can’t figure it out
dusya [7]

Answer:

\large\boxed{\dfrac{41p}{70q^4(r-9)^2}}

Step-by-step explanation:

\dfrac{2p^4}{5q^5(r-9)^3}\cdot\dfrac{41q(r-9)}{28p^3}\\\\=\dfrac{2\!\!\!\!\diagup^1\cdot41}{5\cdot28\!\!\!\!\!\diagup_{14}}\cdot\dfrac{q\!\!\!\!\diagup}{q^{5\!\!\!\!\diagup^4}}\cdot\dfrac{(r\!\!\!\!\!\!{--}-9)\!\!\!\!\!\!{--}}{(r-9)^{3\!\!\!\!\diagup^2}}\cdot\dfrac{p^{4\!\!\!\!\diagup}}{p^3\!\!\!\!\!\!\diagup}\\\\=\dfrac{41}{70}\cdot\dfrac{1}{q^4}\cdot\dfrac{1}{(r-9)^2}\cdot\dfrac{p}{1}\\\\=\dfrac{41p}{70q^4(r-9)^2}

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3 years ago
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