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jonny [76]
3 years ago
14

Which quotient is greater than 3? 42 ÷ 19 40 ÷ 18 38 ÷ 14 36 ÷ 11

Mathematics
1 answer:
docker41 [41]3 years ago
4 0
36/11= 3.2 which is greater than 3
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Which of the following inequalities is true for ALL real values of x?
attashe74 [19]
(2x)2 > 3x2 is true the first two you can not have two x’s on the same side because where would you put them both when solving them the last one I’m not sure about
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3 years ago
21-x=13 telllllllllll mee​
BaLLatris [955]

Answer:

x = 8

Step-by-step explanation:

21-x=13 \\ x = 21 - 13 \\ x = 8

4 0
3 years ago
Read 2 more answers
PLEASE HELP NEED THIS ANSWERED CORRECTLY
Helen [10]

f(3) = 1.9

Solution:

Given function:

$f(x)=\frac{14}{7+2 e^{-0.6 x}}

To find f(3):

Substitute x = 3 in the given function.

$f(3)=\frac{14}{7+2 e^{-0.6 (3)}}

$f(3)=\frac{14}{7+2 e^{-1.8}}

Let us first simplify 2e^{-1.8}.

Apply exponent rule: a^{-b}=\frac{1}{a^{b}}

$ 2e^{-1.8}=2\frac{1}{e^{1.8}}$

The value of e^{1.8}=6.04964. (using calculator)

$\frac{2}{e^{1.8}}=\frac{2}{6.04964}=0.33059

2e^{-1.8}=0.33059

Substitute this value in f(3).

$f(3)=\frac{14}{7+0.33059}

$f(3)=\frac{14}{7.33059}  

$f(3)=1.90980

f(3) = 1.9

Hence the value of f(3) is 1.9.

3 0
3 years ago
Shelly earns 11.45$ per hour. last week she worked 37 1/5 hours.how much did she earn last week
mojhsa [17]
The total amount that Shelley earned is $423.88.
7 0
4 years ago
What is the value of 11x^-3 y^-1 <br> for x=-1 and y=2
andrey2020 [161]

Answer:

  -11/2

Step-by-step explanation:

Put the numbers into the expression and do the arithmetic.

  11(-1)^{-3}2^{-1}=\dfrac{11}{(-1)^3}\cdot\dfrac{1}{2^1}=\dfrac{-11}{2}

3 0
3 years ago
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