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Mrac [35]
3 years ago
14

Plz help..................................... ​

Mathematics
1 answer:
Andre45 [30]3 years ago
7 0

7

7x5=35

7x5^2=175

5x5=25

7x5^3=875

5x5x5=125

7x5^4=4375

5x5x5x5=625

add them :>

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(1 point) Let f be a periodic function of period 10 such that f(x)=x2 for −5≤x<5. Then the Fourier series of f is
ehidna [41]

Answer:

The answer is "\frac{25}{3}".

Step-by-step explanation:

please find the complete question in the attached file.

a_0=\frac{1}{10}\int^{5}_{x=-5} x^2 dx\\

   =\frac{1}{10} (\frac{x^3}{3})^{5}_{-5}\\\\=\frac{1}{30}[5^3+5^3]\\\\=\frac{2}{30}(125)\\\\=\frac{1}{15} \times 125\\\\=\frac{25}{3}

7 0
3 years ago
If the nth term is nn+1, then the (n+1)st term is:
inn [45]

Answer:

\large \boxed{\sf C. \  (n+1)^{n+1}+1}

Step-by-step explanation:

n^n+1

Plug in the value for n as n+1 in the nth term to find the (n+1)st term.

(n+1)^{n+1}+1

5 0
3 years ago
Is 2x+10 = -2(x-5) equals
faust18 [17]
First distribute -2 to both x and -5

-2(x) = -2x
-2(-5) = 10

2x + 10 = -2x + 10

False. 2x + 10 ≠ -2x + 10

False is your answer

hope this helps
3 0
4 years ago
Read 2 more answers
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