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jarptica [38.1K]
3 years ago
14

Figure 1 is dilated to get Figure 2. What is the scale factor? can you simplify it to please

Mathematics
2 answers:
JulijaS [17]3 years ago
6 0
It would be times 1/3
12345 [234]3 years ago
6 0
It’s would be 1/3 explanation
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PLEASE HELP ASAP!:<br><br> Solve for a and b<br> 6a-b=-5<br> 4a-3b = -8
klemol [59]

Answer:

a = -1/2

b = 2

Step-by-step explanation:

Step 1: Rewrite 1st equation

-b = -5 - 6a

b = 5 + 6a

Step 2: Substitution

4a - 3(5 + 6a) = -8

Step 3: Solve

4a - 15 - 18a = -8

-14a - 15 = -8

-14a = 7

a = -1/2

Step 4: Plug in <em>a</em> to find <em>b</em>

6(-1/2) - b = -5

-3 - b = -5

-b = -2

b = 2

7 0
3 years ago
If n is a positive integer, how many 5-tuples of integers from 1 through n can be formed in which the elements of the 5-tuple ar
sleet_krkn [62]

This question is incomplete, the complete question is;

If n is a positive integer, how many 5-tuples of integers from 1 through n can be formed in which the elements of the 5-tuple are written in increasing order but are not necessarily distinct.

In other words, how many 5-tuples of integers  ( h, i , j , m ), are there with  n ≥ h ≥ i ≥ j ≥ k ≥ m ≥ 1 ?

Answer:

the number of 5-tuples of integers from 1 through n that can be formed is [ n( n+1 ) ( n+2 ) ( n+3 ) ( n+4 ) ] / 120

Step-by-step explanation:

Given the data in the question;

Any quintuple ( h, i , j , m ), with n ≥ h ≥ i ≥ j ≥ k ≥ m ≥ 1

this can be represented as a string of ( n-1 ) vertical bars and 5 crosses.

So the positions of the crosses will indicate which 5 integers from 1 to n are indicated in the n-tuple'

Hence, the number of such quintuple is the same as the number of strings of ( n-1 ) vertical bars and 5 crosses such as;

\left[\begin{array}{ccccc}5&+&n&-&1\\&&5\\\end{array}\right] = \left[\begin{array}{ccc}n&+&4\\&5&\\\end{array}\right]

= [( n + 4 )! ] / [ 5!( n + 4 - 5 )! ]

= [( n + 4 )!] / [ 5!( n-1 )! ]

= [ n( n+1 ) ( n+2 ) ( n+3 ) ( n+4 ) ] / 120

Therefore, the number of 5-tuples of integers from 1 through n that can be formed is [ n( n+1 ) ( n+2 ) ( n+3 ) ( n+4 ) ] / 120

4 0
3 years ago
-x&lt;-x+7(x-2) include all of the steps to how you found your answer!
Lady bird [3.3K]
-x<-x+7(x-2)
-x<-x+7x-14 Distribute the 7
-x<6x-14 Combine like terms
-7x<-14 Move all variables to one side
x>2 Divide by -7 to isolate the variable
6 0
3 years ago
Write an equation of the line that goes through the point (6, 12) and has a slope of 2 3 .
Degger [83]

Answer:

3y = 2x + 24

Step-by-step explanation:

The correct question is as follows;

Write an equation of the line that goes through the point (6, 12) and has a slope of 2/3

Solution

Here, we have a point and a slope, and we want to write the equation of the line

The method we shall use here is the point slope method

Mathematically, that will be;

y-y1 = m(x-x1)

(x1,y1) = (6,12)

m = 2/3

y-12 = 2/3(x-6)

3(y-12) = 2(x-6)

3y-36 = 2x - 12

3y = 2x -12 + 36

3y = 2x + 24

8 0
3 years ago
dont want to go to summer school would be so thankful to anyone who could help me with this math problem
Zigmanuir [339]
Looks like you going to summer school
4 0
2 years ago
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