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jarptica [38.1K]
3 years ago
14

Figure 1 is dilated to get Figure 2. What is the scale factor? can you simplify it to please

Mathematics
2 answers:
JulijaS [17]3 years ago
6 0
It would be times 1/3
12345 [234]3 years ago
6 0
It’s would be 1/3 explanation
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PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!
Viktor [21]

Answer:

Step-by-step explanation:

Triangle IJK is a right angle triangle.

From the given right angle triangle

JK represents the hypotenuse of the right angle triangle.

With ∠K as the reference angle,

IK represents the adjacent side of the right angle triangle.

IJ represents the opposite side of the right angle triangle.

To determine Cos K, we would apply trigonometric ratio

Cos θ = adjacent side/hypotenuse. Therefore,

Cos K = 36/85

Cos K = 0.4235

Rounding up to the nearest hundredth,

Cos K = 0.42

4 0
3 years ago
PLZZZ HELP!!! VERY CONFUSED!!! Will give brainliest!!!!
777dan777 [17]

By the intersecting chords theorem, you have

7\cdot4=5\cdot x\implies 5x=28\implies\boxed{x=\dfrac{28}5}

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3 years ago
Bills plant grew at the rate of 1 1/2. How tall would the plant be after 3 weeks
kvv77 [185]

Answer:

9/2 or 4 1/2

Step-by-step explanation:

you do 1 1/2 times 3

3/2 times 3 equals

7 0
3 years ago
Read 2 more answers
Jeremy can row 2/3 of a mile in 1/4 of an hour. What is the unit rate that describes the miles per hour?
svet-max [94.6K]
2.6 repeating miles per hour
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3 years ago
An employer has a staff of eighty actuaries, ten of whom are student actuaries. A student actuary is allowed a total of ten week
sergiy2304 [10]

Answer:

0.1111

Step-by-step explanation:

From the given information;

Number of staffs in the actuary = 80

Out of the 80, 10 are students.

i.e.

P(student actuary) = 10/80 = 0.125

number of weeks in a year = 52

off time per year = 10/52 = 0.1923

P(at work || student actuary) = (50 -10/52)

= 42/52

= 0.8077

P(non student actuary) = (80 -10)/80

= 70 / 80

= 0.875

For a non-student, they are only eligible to 4 weeks off in a year

i.e.

P(at work | non student) = (52-4)/52

= 48/52

= 0.9231

∴

P(at work) = P(student actuary) × P(at work || student actuary) + P(non student actuary) × P(at work || non studnet actuary)

P(at work) =  (0.125 × 0.8077) + ( 0.875 × 0.9231)

P(at work) = 0.1009625 + 0.8077125

P(at work) = 0.90868

Finally, the P(he is a student) = (P(student actuary) × P(at work || student actuary) ) ÷ P(at work)

P(he is a student) = (0.125 × 0.8077) ÷ 0.90868

P(he is a student) = 0.1009625 ÷ 0.90868

P(he is a student) = 0.1111

5 0
3 years ago
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