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3 years ago

The solution set of n2 − 14n = -45 is {____}.

Mathematics

1 answer:

prisoha [69]3 years ago

5 0

I solved it with n^2

Solution: (5,9)

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19. Use the unit circle to find the value of tan 315º.<br> Show work pls.

Free_Kalibri [48]

Answer: -1

Step-by-step explanation:

First change tan(315) to:

$\frac{\sin(315)}{\cos(315)}$

Then evaluate the sine and cosine function. What is the y component of 315 degrees? What is the x component of 315 degrees?

$-\frac{\sqrt{2} }{2} /\frac{\sqrt{2} }{2} =-1$

7 0

3 years ago

Eva maintained an average speed of 35 miles per hour (mph) for the first m hours of her road trip. For the next n hours of the t

Schach [20]

Answer:

Step-by-step explanation:

I don't see the choices, but I will make the equations that seems to be correct to me.

Known facts:

maintained an average speed of 35 miles per hour (mph) for the first m hours of her road trip.
next n hours of the trip, she drove at an average speed of 60 mph.
Eva drove a total of 225 miles in 4.5 hours.

Let's make the equations:

m + n = 4.5

35m + 60n = 225

Hope that helps!

7 0

3 years ago

Write the equation of the line fully simplified slope-intercept from.

galben [10]

Answer:

y = 4/3x - 7

Step-by-step explanation:

5 0

3 years ago

Y’all please help me with this I don’t understand

lakkis [162]

Answer: x=12

Step-by-step explanation:

3 0

3 years ago

10. A movie theater advertises that a family of two adults, one student, and one child between the ages of 3

BlackZzzverrR [31]

Answer:

Students ticket = $4

Child ticket = $1

Adult ticket = $5

Step-by-step explanation:

Let the price of the student ticket be $x and the price of a child ticket be $y. An adult ticket costs as much as the combined cost of a student ticket and a child ticket, so the price of one adult ticket is $(x+y).

1. A movie theater advertises that a family of two adults, one student, and one child between the ages of 3 and 8 can attend a movie for $15. Then

$2(x+y)+x+y=15$

2. If you purchase 1 adult ticket, 4 student tickets, and 2 child tickets for $23, then

$(x+y)+4x+2y=23$

Now, solve the system of two equations:

$\left\{\begin{array}{l}2(x+y)+x+y=15\\ \\(x+y)+4x+2y=23\end{array}\right.\Rightarrow \left\{\begin{array}{l}3(x+y)=15\\ \\5x+3y=23\end{array}\right.\\ \\\left\{\begin{array}{l}x+y=5\\ \\5x+3y=23\end{array}\right.\\ \\\left\{\begin{array}{l}y=5-x\\ \\5x+3(5-x)=23\end{array}\right.$

Solve the last equation

$5x+15-3x=23\\ \\2x=23-15\\ \\2x=8\\ \\x=4\\ \\y=5-x=5-4=1$

Students ticket = $4

Child ticket = $1

Adult ticket = $5

8 0

3 years ago

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