Answer:
4/25 = 0.16
Step-by-step explanation:
The shortest stick must be between 0 and 5/3. The probability that it is longer than 1 is therefore:
(5/3 − 1) / (5/3 − 0)
(2/3) / (5/3)
2/5
So the probability that both of the shortest sticks are longer than 1 is (2/5)² = 4/25.
Answer:
Eli
Step-by-step explanation:
Arjun: 20÷3=6.6666666667
6.6666666667mL of chocolate syrup for every ounce of hot water.
Eli: 45÷6=7.5
7.5mL of chocolate syrup for every ounce of hot water
Conclusion: Eli has the hot cocoa with the most chocolate
Answer:
2H2S (g) + 3O2 (g) → 2H2O (l) + 2SO2 (g)
Calculate ΔH° from the given data. Is the reaction exothermic or endothermic?
ΔH°f (H2S) = -20.15 kJ/mol; ΔH°f (O2) = 0 kJ/, mol; ΔH°f (H2O) = -285.8 kJ/mol; ΔH°f (SO2) = -296.4 kJ/mol
Answer:
111111
1111110 is the simple expression.
Step-by-step explanation:
The expression to be solved:
![\dfrac{6,666,666\times666,666 }{1+2+3+4+5+6+5+4+3+2+1} - \dfrac{777,777\times777,777}{1+2+3+4+5+6+7+6+5+4+3+2+1}](https://tex.z-dn.net/?f=%5Cdfrac%7B6%2C666%2C666%5Ctimes666%2C666%20%7D%7B1%2B2%2B3%2B4%2B5%2B6%2B5%2B4%2B3%2B2%2B1%7D%20-%20%5Cdfrac%7B777%2C777%5Ctimes777%2C777%7D%7B1%2B2%2B3%2B4%2B5%2B6%2B7%2B6%2B5%2B4%2B3%2B2%2B1%7D)
First of all, let us solve the first term:
![\dfrac{6,666,666\times666,666 }{1+2+3+4+5+6+5+4+3+2+1}\\\Rightarrow \dfrac{6666666\times666666 }{36}\\\Rightarrow \dfrac{6666666\times666666 }{6\times 6}\\\Rightarrow 1111111\times 111111](https://tex.z-dn.net/?f=%5Cdfrac%7B6%2C666%2C666%5Ctimes666%2C666%20%7D%7B1%2B2%2B3%2B4%2B5%2B6%2B5%2B4%2B3%2B2%2B1%7D%5C%5C%5CRightarrow%20%5Cdfrac%7B6666666%5Ctimes666666%20%7D%7B36%7D%5C%5C%5CRightarrow%20%5Cdfrac%7B6666666%5Ctimes666666%20%7D%7B6%5Ctimes%206%7D%5C%5C%5CRightarrow%201111111%5Ctimes%20111111)
Now, the right term:
![\dfrac{777777\times777777}{1+2+3+4+5+6+7+6+5+4+3+2+1}\\\Rightarrow \dfrac{777777\times777777}{49}\\\Rightarrow \dfrac{777777\times777777}{7 \times 7}\\\Rightarrow 111111 \times 111111](https://tex.z-dn.net/?f=%5Cdfrac%7B777777%5Ctimes777777%7D%7B1%2B2%2B3%2B4%2B5%2B6%2B7%2B6%2B5%2B4%2B3%2B2%2B1%7D%5C%5C%5CRightarrow%20%5Cdfrac%7B777777%5Ctimes777777%7D%7B49%7D%5C%5C%5CRightarrow%20%5Cdfrac%7B777777%5Ctimes777777%7D%7B7%20%5Ctimes%207%7D%5C%5C%5CRightarrow%20111111%20%5Ctimes%20111111)
So, the expression to be solved becomes:
![1111111\times 111111-111111\times 111111\\\Rightarrow 111111(1111111-1)\\\Rightarrow 111111\times 1111110](https://tex.z-dn.net/?f=1111111%5Ctimes%20111111-111111%5Ctimes%20111111%5C%5C%5CRightarrow%20111111%281111111-1%29%5C%5C%5CRightarrow%20111111%5Ctimes%201111110)
Answer:
35/16 sec ( 2 3/16 sec)
Step-by-step explanation:
This assumes you glove is at height = 0
0 = -16t^2 + 35t
0 = t ( -16t + 35) shows t = 0 ( before you throw it) and t = 35/16 sec