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Archy [21]
2 years ago
8

in a game the player wins if he rolls a 6 on a number cube if the number cube is rolled 18 times then what is a reasonable predi

ction of unsucessful rolls
Mathematics
1 answer:
Dmitry_Shevchenko [17]2 years ago
6 0

Answer:

There would be 15 unsuccessful rolls

Step-by-step explanation:

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What is 50=5/9(F-32)
Charra [1.4K]

Answer: F=122

Step-by-step explanation:

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2 years ago
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What is 0.212121 written as a fraction?
Norma-Jean [14]
It's 21212121
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3 years ago
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how would you estimate the sum? just like estimate the fractions and then get your estimated answer? Q: 2 1/6 + 3 6/11
denis-greek [22]
I think estimation is terrible. If u want to truly solve it, you just need to get a common denominator on each of the fractions. that means the bottom half of both fractions must be the same in addition or subtraction. so here, the common denominator would be 66. What times 6 = 66? 11. So 1*11/6*11 = 11/66. Then what times 11 = 66? 6. So 6*6/6*11. Your new problem is 2 11/66 + 3 36/66. Now you can just add it up, but the denominators will always stay the same, 66. Your answer would be 5 47/66
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3 years ago
What is a quadrilateral?
Brut [27]
A four-sided shape/figure
8 0
3 years ago
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Can u help me on this plzz
avanturin [10]
Median: 29
Range: 25
IQR: 14.5

Explanations:

**Median:**
(To find the median, we need to first order all the elements)

Ordered —> 15, 18, 18, 20, 23, 28, 30, 33, 33, 34, 38, 40

(Since there are an even number of elements, we need to add the two elements in the middle and divide by 2)

Median = (28 + 30)/2 = 58/2 = 29

**Range:**

(To find the range, you just have the subtract the smallest one from the largest)

Range = 40 - 15 = 25

**IQR:**

First half of elements —> 15, 18, 18, 20, 23, 28
Second half of elements —> 30, 33, 33, 34, 38, 40

Q1 (Quartile 1) = Median of first half = (18 + 20)/2 = 38/2 = 19
Q3 (Quartile 3) = Median of second half = (33 + 34)/2 = 67/2 = 33.5

IQR = Q3 - Q1 = 33.5 - 19 = 14.5
5 0
2 years ago
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