Answer:
{
x
∣
x
>
1
} or x
∈
(
1
,
∞
)
Step-by-step explanation:
2
x
+
3
>
7
⇒
2
x
>
4
(subtract 3 from both sides)
2
x
+
3
>
7
⇒
x
>
2
(divide both sides by 2)
2
x
+
9
>
11
⇒ 2
x
>
2
(subtract 9 from both sides)
2
x
+
9
>
11
⇒
x
>
1
(divide both sides by 2)
if an x
-value is greater than 2, it will automatically be greater than 1. Thus, the solution set for 2
x+
3
>
7 is a subset of the one for 2
x
+
9
>11
.That means, all we need to do here is list the solution set for 2
x
+
9
>
11
, and we're done.
The solution set we need is simply "all x such that x is greater than 1", or {
x
∣
x
>
1
}
or
x
∈
(
1
,
∞
)
Answer:
False,False,True,False,True
Step-by-step explanation:
Hope this helps, I guarantee!
440 = 1 x 2 x 2 x 2 x 5 x 11
(1): 1 x 440
(2): 2 x 220
(2 x 2): 4 x 110
(5): 5 x 88
(2x2x2): 8 x 55
(2 x 5): 10 x 44
(11): 11 x 40
(2x2x5): 20 x 22
No need to continue because the next number is 2 x 11 = 22 and we already have that on the right side, so we have found all of the multiplicative pairs of 440.
Answer:
Step-by-step explanation:
Let the remainder of the diameter is x.
<u>Use the intersecting chords theorem:</u>
- 6*x = (72/2)*(72/2)
- 6x = 1296
- x = 216
<u>The diameter:</u>
- d = 6 + x = 6 + 216 = 222 in
<u>The radius:</u>
The answer is 9. Thank you for your time