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3 years ago

Pls help I need a good grade

Mathematics

1 answer:

postnew [5]3 years ago

7 0

Step-by-step explanation:

m+n

2..................

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We decided that the movie night will last four hours each movie takes 1.75 hours and we want to make sure we leave a half hour f

Naddik [55]

2 movies
4 hours - .5 popcorn -1.75-1.75=0 Easier terms 4 hours minus 30 min is 3 hours and 30 min left each movie is 1 hour and 45 min plus 1 hour 45 min i that's 2 hours and 90 min 90 min are one hour and 30 min. So 2 hours plus one hour and 30 min is the 3 hours and 30 min are we're left

4 0

3 years ago

What is the solution to the equation below? Round your answer to two decimal places. 4•e^x=17

bixtya [17]

Answer:

$\large\boxed{x\approx1.45}$

Step-by-step explanation:

$4e^x=17\qquad\text{divide both sides by 4}\\\\e^x=\dfrac{17}{4}\qquad \ln\ \text{of both sides}\\\\\ln e^x=\ln\dfrac{17}{4}\qquad\text{use}\ \log_aa^n=n\\\\x=\ln\dfrac{17}{4}\\\\x\approx1.45$

7 0

3 years ago

3. The curve C with equation y=f(x) is such that, dy/dx = 3x^2 + 4x +k

Andreas93 [3]

a. Given that y = f(x) and f(0) = -2, by the fundamental theorem of calculus we have

$\displaystyle \frac{dy}{dx} = 3x^2 + 4x + k \implies y = f(0) + \int_0^x (3t^2+4t+k) \, dt$

Evaluate the integral to solve for y :

$\displaystyle y = -2 + \int_0^x (3t^2+4t+k) \, dt$

$\displaystyle y = -2 + (t^3+2t^2+kt)\bigg|_0^x$

$\displaystyle y = x^3+2x^2+kx - 2$

Use the other known value, f(2) = 18, to solve for k :

$18 = 2^3 + 2\times2^2+2k - 2 \implies \boxed{k = 2}$

Then the curve C has equation

$\boxed{y = x^3 + 2x^2 + 2x - 2}$

b. Any tangent to the curve C at a point (a, f(a)) has slope equal to the derivative of y at that point:

$\dfrac{dy}{dx}\bigg|_{x=a} = 3a^2 + 4a + 2$

The slope of the given tangent line $y=x-2$ is 1. Solve for a :

$3a^2 + 4a + 2 = 1 \implies 3a^2 + 4a + 1 = (3a+1)(a+1)=0 \implies a = -\dfrac13 \text{ or }a = -1$

so we know there exists a tangent to C with slope 1. When x = -1/3, we have y = f(-1/3) = -67/27; when x = -1, we have y = f(-1) = -3. This means the tangent line must meet C at either (-1/3, -67/27) or (-1, -3).

Decide which of these points is correct:

$x - 2 = x^3 + 2x^2 + 2x - 2 \implies x^3 + 2x^2 + x = x(x+1)^2=0 \implies x=0 \text{ or } x = -1$

So, the point of contact between the tangent line and C is (-1, -3).

7 0

2 years ago

Without graphing is the system independent, dependent, or inconsistent?

rewona [7]

Y = -2 x - 9
3 x - 4(-2 x - 9 ) = -8
3 x + 8 x + 36 = - 8
11 x = - 44, x = - 4
y = 8 - 9 , y = -1
This is a unique solution, the system is independent.

3 0

3 years ago

Question: Image Below

konstantin123 [22]

Answer:

The answer will be: C: 2t + 10

Step-by-step explanation:

You can check the answer by replacing t with any number.

Example:

I want to find the perimeter for 3 triangles. Here's how I would write the equation.

2(3) + 10 = 6 + 10 = 16

We can check by adding all the sides for three triangles.

2 + 2 + 2 + 5 + 5 = 16

Hope this helped :)

5 0

2 years ago