State if the three numbers can be the measures of the sides of a triangle.

a rocket is 1 mile above thw earth in 30 seconds and 5 miles above the earth in 2.5 minutes what is the rockets rate of change i

Veronika [31]

Rate of Change:

At 1 mile in 30 seconds.
At 5 miles in 2.5 minutes. 2.5 minutes = 2.5*60 = 150 seconds.

Rate of change = Change in height / Change in time

= (h₂-h₁)/(t₂-t₁)

= (5 -1) /(150 -30) = 4/120 = (1/30) = 0.0333 miles per second.

   = (1/30) miles per second or 0.0333 miles per second.

To have the answer in miles per minute.

   (1/30) miles per second = (1/30) miles/second.

60 seconds = 1minute
1 second = (1/60) minute.

(1/30) miles/second = (1/30) miles/(1/60)minute
   = (1/30) *60 miles / minute
   =    2 miles per minute.

8 0

3 years ago

your weight on earth's moon is 2/6 your weight on earth. if a person weighed 120 pounds on earth what would be her weight on the

miv72 [106K]

Well, 120 * 1/3 is 40 pounds, so 40.

3 0

3 years ago

Evaluate the line integral: Int(x^2 dx +y^2 dy) ∫Cx2dx+y2dy C consists of the arc of the circle x^2+y^2=4 from (2,0) to (0,2) fo

pychu [463]

The first part of the arc $C$ can be parameterized by

$C_1:\mathbf r(t)=\langle 2\cos t,2\sin t\rangle$

with $0\le t\le\dfrac\pi2$ , and the second part by

$C_2:\mathbf s(t)=(1-t)\langle0,2\rangle+t\langle4,3\rangle=\langle4t,2+t\rangle$

with $0\le t\le 1$ .

Now the line integral can be computed.

$\displaystyle\int_{C=C_1\cup C_2}(x^2\,\mathrm dx+y^2\,\mathrm dx)=\int_0^{\pi/2}\left((2\cos t)^2\dfrac{\mathrm d}{\mathrm dt}(2\cos t)+(2\sin t)^2\dfrac{\mathrm d}{\mathrm dt}(2\sin t)\right)\,\mathrm dt+\int_0^1\left((4t)^2\dfrac{\mathrm d}{\mathrm dt}(4t)+(2+t)^2\dfrac{\mathrm d}{\mathrm dt}(2+t)\right)\,\mathrm dt$
$=\displaystyle\int_0^{\pi/2}(-8\cos^2t\sin t+8\sin^2t\cos t)\,\mathrm dt+\int_0^1(64t^2+(2+t)^2)\,\mathrm dt$
$=\displaystyle-8\int_0^{\pi/2}\sin t\cos t(\cos t-\sin t)\,\mathrm dt+\int_0^1(65t^2+4t+4)\,\mathrm dt$
$=\displaystyle-4\int_0^{\pi/2}\sin2t(\cos t-\sin t)\,\mathrm dt+\int_0^1(65t^2+4t+4)\,\mathrm dt$
$=\displaystyle-2\int_0^{\pi/2}(\sin t+\sin3t-\cos t+\cos3t)\,\mathrm dt+\int_0^1(65t^2+4t+4)\,\mathrm dt$
$=\displaystyle-2\left(-\cos t-\frac{\cos3t}3-\sin t+\frac{\sin3t}3\right)\bigg|_{t=0}^{t=\pi/2}+\left(\frac{65}3t^3+2t^2+4t\right)\bigg|_{t=0}^{t=1}$
$=0+\dfrac{83}3$
$=\dfrac{83}3$

5 0

3 years ago

What is the total surface area of this prism?

Basile [38]

Answer:

Step-by-step explanation:

let us calculate area of pentagon.

it consists of 5 isosceles triangles with base=5 cm

apothem h=3.6 cm

area of pentagon=5×1/2×5×3.6≈45 cm

area of 2 pentagons (top and bottom)=2×45=90 cm²

lateral area of 6 rectangles=2(10×5+10×5+10×5)=2(50+50+50)=300 cm²

Total surface area=90+300=390 cm²

7 0

3 years ago

LC)Which of the following algebraic expressions can be used to express the statement "three less than a squared?"

adoni [48]

Answer:

A

Step-by-step explanation:

mark me brainliest pls

3 0

3 years ago

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