Answer:
I think it is the power of a power.
Given: line segment AB // to line segment CD, ∠B ≅∠D and line segment BF ≅ to line segment ED. Prove: Δ ABF ≅ Δ CED.
Follow the matching numbers on the statement versus reason chart.
Statement:
1. line segment AB // to line segment CD.
2. ∠B ≅∠D
3. line segment BF ≅ to line segment ED.
4. ∠A ≅∠C
5. Δ ABF ≅ Δ CED
Reason:
1. Given
2. Given
3. Given
4. Alternate interior angles are congruent.
5. Corresponding parts of congruent triangles are congruent.
Answer:
2700!
Step-by-step explanation:
hope that helped <3
Answer and step-by-step explanation:
The polar form of a complex number 
is the number 
where 
is called the modulus and 
is called the argument. You can switch back and forth between the two forms by either remembering the definitions or by graphing the number on Gauss plane. The advantage of using polar form is that when you multiply, divide or raise complex numbers in polar form you just multiply modules and add arguments.
(a) let's first calculate moduli and arguments
now we can write the two numbers as
(b) As noted above, the argument of the product is the sum of the arguments of the two numbers:
(c) Similarly, when raising a complex number to any power, you raise the modulus to that power, and then multiply the argument for that value.
![(z_1)^1^2=[4e^{-i\frac \pi6}]^1^2=4^1^2\cdot (e^{-i\frac \pi6})^1^2=2^2^4\cdot e^{-i(12)\frac\pi6}\\=2^2^4 e^{-i\cdot2\pi}=2^2^4](https://tex.z-dn.net/?f=%28z_1%29%5E1%5E2%3D%5B4e%5E%7B-i%5Cfrac%20%5Cpi6%7D%5D%5E1%5E2%3D4%5E1%5E2%5Ccdot%20%28e%5E%7B-i%5Cfrac%20%5Cpi6%7D%29%5E1%5E2%3D2%5E2%5E4%5Ccdot%20e%5E%7B-i%2812%29%5Cfrac%5Cpi6%7D%5C%5C%3D2%5E2%5E4%20e%5E%7B-i%5Ccdot2%5Cpi%7D%3D2%5E2%5E4)
Now, in the last step I've used the fact that 
, or in other words, the complex exponential is periodic with 
as a period, same as sine and cosine. You can further compute that power of two with the help of a calculator, it is around 16 million, or leave it as is.
Answer:
and 
Step-by-step explanation:
The equation of the isotope decay is:
14-Carbon has a half-life of 5568 years, the time constant of the isotope is:
The decay time is:
(There is no a year 0 in chronology).
Lastly, the relative amount is estimated by direct substitution:
