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julsineya [31]
2 years ago
11

Which quadratic regression equation best fits the data set?

Mathematics
1 answer:
loris [4]2 years ago
7 0

Answer: y=2.608x^2-115.264x+1568.064

Step-by-step explanation:

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Dylan is 15, which is 3 years older than twice his sister Savannah’s age. How old is savannah
Brrunno [24]

Answer:

Savannah's age = 6 years

Step-by-step explanation:

Let

Savannah's age = x

Dylan's age = 15

Dylan is 15, which is 3 years older than twice his sister Savannah’s age

Dylan = 2x + 3

Find Savannah's age

2x + 3 = 15

Subtract 3 from both sides

2x + 3 - 3 = 15 - 3

2x = 12

Divide both sides by 2

2x / 2 = 12 / 2

x = 6

Therefore,

Savannah's age = x

= 6 years

Dylan's age = 2x +3

= 2*6 + 3

= 12 + 3

= 15 years

4 0
3 years ago
Given the following linear function sketch the graph of the function and find the domain and range. for F(x)=2/7x -2
Igoryamba

y =  \frac{2}{7} x - 2
domain and range are both all real numbers :)

7 0
3 years ago
In the flowering plant, white flowers (B) are dominant over red flowers (b), and short plants (E) are dominant over tall flower
lutik1710 [3]

<u>Question Completion</u>

(a)What is your null hypothesis?

(b)What is your expected phenotypic ratio based on Mendelian inheritance?

(c)Calculate the expected number of flowers you should have gotten based on the Mendelian inheritance. Then calculate a chi-square value, degrees of freedom, and a p-value.

  • Chi-square statistic: _____
  • Degrees of freedom (# phenotypes -1):
  • P-value:

(d)Interpret your results. Do you reject it or fail to reject your null hypothesis (please restate the null)?

Answer:

(a)H_0:$The given data fit the predicted phenotype

(b)9:3:3:1

(c)

  • Chi-square statistic: 3.8914
  • Degrees of freedom (# phenotypes -1) =3
  • P-value:  0.2734

(d)We fail to reject the null hypothesis.

Step-by-step explanation:

In the flowering plant, white flowers (B) are dominant over red flowers (b), and short plants (E) are dominant over tall flowers (e). An F2 generation was created by crossing two F1 individuals (each BbEe).

(a)The null hypothesis is:

H_0:$The given data fit the predicted phenotype

(b)The gametes are BE, Be, bE and be.

The offsprings are presented in the table below:

\left|\begin{array}{c|cccc}&BE&Be&bE&be\\--&--&--&--&--\\BE&BE&BE&BE&BE\\Be&BE&Be&BE&Be\\bE&BE&BE&bE&bE\\be&BE&Be&bE&be\end{array}\right|

The expected phenotypic ratio based on Mendelian inheritance

BE:Be:bE:be=9:3:3:1

(c)

\left|\begin{array}{c|c|c|c|c|c}$Phenotype&Observed&$Expected&O-E&(O-E)^2&\dfrac{(O-E)^2}{E} \\-----&--&--&--&--&--\\$White short(BE)&206&\frac{9}{16}*404 \approx 227 &-21&441&1.9427\\$Red, short(bE)&83&\frac{3}{16}*404 \approx 78 &5&25&0.3205\\$White, tall(Be)&85&\frac{3}{16}*404 \approx 78 &7&49&0.6282\\$Red, tall(be)&30&\frac{1}{16}*404 \approx 25 &5&25&1\\-----&--&--&--&--&--\\$Total&404&--&--&--&3.8914\end{array}\right|

Therefore:

  • Chi-square statistic: 3.8914
  • Degrees of freedom (# phenotypes -1):  4-1 =3
  • P-value:  0.2734

(d) Our null hypothesis is:

H_0:$The given data fit the predicted phenotype

Since p>0.05, the given data fit the predicted phenotypic ratio.

We, therefore, fail to reject the null hypothesis.

The difference in the observed and expected are sosmall that they can be attributed to random chance.

8 0
3 years ago
Meg started her trip with 11½ gallons of gas in her car's tank. She bought an additional 6 4/5 gallons on her trip and arrived b
Anit [1.1K]
11 1/2+6 4/5 equals? So, you have to make each fraction have the same denominator. So, you would notice that they have in LCD (least common denominator )which is 10. So you're new fractions are 11 5/10+ 6 8/10. 11+6=17. 5/10+8/20=13/10. Which simplified it would be 1 3/10. 17+1 3/10 equals 18 3/10. 18 3/10 -3 3/10 equals 15. 15 is the answer.
8 0
3 years ago
Chance flips a coin and rolls a 1 - 6 number cube. What is the probability that he rolls a number less than 4 and the coin lands
inna [77]
3/6 and 1/2 hoped that helped

4 0
3 years ago
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