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3 years ago

Pls Help Me With This Question! It's 8th Grade Math!

Mathematics

2 answers:

Andre45 [30]3 years ago

8 0

Answer:

y= 4/3x

Step-by-step explanation:

Mademuasel [1]3 years ago

5 0

Answer:

y= 4/3x

Step-by-step explanation:

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5000

melisa1 [442]

Answer:

can u ;ut it in english plzz

Step-by-step explanation:

8 0

3 years ago

There are 10 multiple choice questions in an examination. first 4 have 5 choices each and remaining have 4 choices each. how man

stira [4]

2560000 sequences of answers are possible.

Explanation

Total number of questions = 10

First 4 questions have 5 choices each and remaining (10-4)= 6 questions have 4 choices each.

So, the possible sequences of answers for first 4 questions $= 5^4 = 625$

and the possible sequences of answers for remaining 6 questions $= 4^6=4096$

Thus, the total possible number of sequences of answers = (625 × 4096) = 2560000

5 0

3 years ago

Read 2 more answers

When crossing a street

Paul [167]

C! youve got it dude !!!

5 0

3 years ago

Read 2 more answers

Find the nth degree polynomial function with real coefficients satisfying the given conditions.

RUDIKE [14]

$\bf (x+1)(x-3)(x-2-4i)(x-2+4i)
\\\\
\textit{now, let's take a peek at }(x-2-4i)(x-2+4i)\\
\textit{and recall our }\textit{difference of squares}
\\ \quad \\
(a-b)(a+b) = a^2-b^2\qquad \qquad 
a^2-b^2 = (a-b)(a+b)\\\\
-----------------------------\\\\
(x-2-4i)(x-2+4i)\implies [(x-2)-(4i)][(x-2)+(4i)]
\\\\\
[(x-2)^2-(4i)^2]\implies [(x^2-2x+4)-(4^2\boxed{i^2})]
\\\\\
[(x^2-2x+4)-(16\cdot \boxed{-1})]\implies [(x^2-2x+4)+16]
\\\\
(x^2-2x+20)\\\\
-----------------------------$

$\bf thus
\\\\

\begin{array}{llll}
(x+1)(x-3)\\(x-2-4i)(x-2+4i)
\end{array}\implies (x+1)(x-3)(x^2-2x+20)
\\\\\\
(x^2-2x-3)(x^2-2x+20)\implies 
\begin{array}{llll}
x^4-2x^3+20x^2-2x^3\\+4x^2-40x+3x^2-6x+60
\end{array}
\\\\\\
x^4-4x^3+27x^2-46x+60$

4 0

3 years ago

Can you resolve this? A= Area P= Perimeter AT= Total Area plis help D:

Paraphin [41]

Answer:

in steps

Step-by-step explanation:

upper square: P = 20x² + 8

side: P/4 = 5x² + 2

A = side² = (5x² + 2)² = 25x⁴ + 20x² + 4

Middle equilateral Triangle: A = x² + 4x + 4 base = 2x + 4

A = base x height / 2

(x + 2)² = 2 (x + 2) x height /2

height = x + 2

perimeter = 2 (x + 2) x 3 = 6x + 12

Lower trapezoid: A₁ = 2x² + 24x + 40 = 2 (x² + 12x + 20) = 2 (x + 2) (x + 10)

A₁ = (x + 10)² = 2 (x + 2) (x + 10)

x + 10 = 2x + 4

x = 6

A₂ = (2x + 4) (x + 10) / 2 = (16 x 16) / 2 = 128

A₁ = (6 + 10)² = 256

AT = 256 + 128 = 384

6 0

3 years ago