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3 years ago

11

The length of a rectangular frame is 15 inches , and the width of the frame is 8 inches . What is the length of a diagonal of th

is frame in inches ?

1 answer:

KATRIN_1 [288]3 years ago

3 0

Answer:

17

Step-by-step explanation:

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For for every ten sheets of stickers you buy at a craft store the total cost increases $20.50

Len [333]

The equation which relates the change in price per sticker purchased is y = 2.05x

The number of stickers purchased = 10

Price change = $20.50

The change in price per sticker purchased can be expressed as :

Price change / number of stickers

Change in price per sticker = $20.50 / 10

Change in price per sticker purchased = 2.05

Therefore, the required equation which related y and x is :

y = 2.05x

Learn more :brainly.com/question/13218948

3 0

2 years ago

1. A triangular swimming pool is an isosceles triangle in shape. The two

Nady [450]

Answer:

Side a = 35ft

Side b = 35ft

Side c = 20ft

Step-by-step explanation:

The formula for the perimeter of a triangle = Side a + Side b + Side c

In an isosceles triangle, 2 sides are equal to each other.

So, Side a = Side b

In the question, we are told that:

The two equal sides are each 5 ft less than twice the length of the third side.

Hence,

a = 2c - 5

b = 2c - 5

P = 90ft

P = a + b + c

90 = 2c - 5 + 2c - 5 + c

Collect like terms

90 = 5c - 10

90 + 10 = 5c

100 = 5c

c = 100/5

c = 20

The length of the third side = 20ft

a = 2c - 5

= 2 × 20 - 5

= 40 - 5

= 35 ft

b =2c - 5

= 2 × 20 - 5

= 40 - 5

= 35 ft

Therefore,

Side a = 35ft

Side b = 35ft

Side c = 20ft

3 0

3 years ago

Plz help! Identify the function represented by the graph or table is linear or nonlinear

Alchen [17]

Left one is linear and the one on the right is nonlinear

8 0

3 years ago

The sum of the squares of 3 consecutive positive integers is 116. What are the numbers?

Elza [17]

You are supposed to use the third option: 3n2 + 6n + 5 = 116.
Take a look at the attachment to see how I got that solution.
Hope it helps! :)

5 0

3 years ago

A triangle is formed from the points L(-3, 6), N(3, 2) and P(1, -8). Find the equation of the following lines:

Dima020 [189]

Answer:

Part A) $y=\frac{3}{4}x-\frac{1}{4}$

Part B) $y=\frac{2}{7}x-\frac{5}{7}$

Part C) $y=\frac{2}{7}x+\frac{8}{7}$

see the attached figure to better understand the problem

Step-by-step explanation:

we have

points L(-3, 6), N(3, 2) and P(1, -8)

Part A) Find the equation of the median from N

we Know that

The median passes through point N to midpoint segment LP

step 1

Find the midpoint segment LP

The formula to calculate the midpoint between two points is equal to

$M(\frac{x1+x2}{2},\frac{y1+y2}{2})$

we have

L(-3, 6) and P(1, -8)

substitute the values

$M(\frac{-3+1}{2},\frac{6-8}{2})$

$M(-1,-1)$

step 2

Find the slope of the segment NM

The formula to calculate the slope between two points is equal to

$m=\frac{y2-y1}{x2-x1}$

we have

N(3, 2) and M(-1,-1)

substitute the values

$m=\frac{-1-2}{-1-3}$

$m=\frac{-3}{-4}$

$m=\frac{3}{4}$

step 3

Find the equation of the line in point slope form

$y-y1=m(x-x1)$

we have

$m=\frac{3}{4}$

$point\ N(3, 2)$

substitute

$y-2=\frac{3}{4}(x-3)$

step 4

Convert to slope intercept form

Isolate the variable y

$y-2=\frac{3}{4}x-\frac{9}{4}$

$y=\frac{3}{4}x-\frac{9}{4}+2$

$y=\frac{3}{4}x-\frac{1}{4}$

Part B) Find the equation of the right bisector of LP

we Know that

The right bisector is perpendicular to LP and passes through midpoint segment LP

step 1

Find the midpoint segment LP

The formula to calculate the midpoint between two points is equal to

$M(\frac{x1+x2}{2},\frac{y1+y2}{2})$

we have

L(-3, 6) and P(1, -8)

substitute the values

$M(\frac{-3+1}{2},\frac{6-8}{2})$

$M(-1,-1)$

step 2

Find the slope of the segment LP

The formula to calculate the slope between two points is equal to

$m=\frac{y2-y1}{x2-x1}$

we have

L(-3, 6) and P(1, -8)

substitute the values

$m=\frac{-8-6}{1+3}$

$m=\frac{-14}{4}$

$m=-\frac{14}{4}$

$m=-\frac{7}{2}$

step 3

Find the slope of the perpendicular line to segment LP

Remember that

If two lines are perpendicular, then their slopes are opposite reciprocal (the product of their slopes is equal to -1)

$m_1*m_2=-1$

we have

$m_1=-\frac{7}{2}$

so

$m_2=\frac{2}{7}$

step 4

Find the equation of the line in point slope form

$y-y1=m(x-x1)$

we have

$m=\frac{2}{7}$

$point\ M(-1,-1)$ ----> midpoint LP

substitute

$y+1=\frac{2}{7}(x+1)$

step 5

Convert to slope intercept form

Isolate the variable y

$y+1=\frac{2}{7}x+\frac{2}{7}$

$y=\frac{2}{7}x+\frac{2}{7}-1$

$y=\frac{2}{7}x-\frac{5}{7}$

Part C) Find the equation of the altitude from N

we Know that

The altitude is perpendicular to LP and passes through point N

step 1

Find the slope of the segment LP

The formula to calculate the slope between two points is equal to

$m=\frac{y2-y1}{x2-x1}$

we have

L(-3, 6) and P(1, -8)

substitute the values

$m=\frac{-8-6}{1+3}$

$m=\frac{-14}{4}$

$m=-\frac{14}{4}$

$m=-\frac{7}{2}$

step 2

Find the slope of the perpendicular line to segment LP

Remember that

If two lines are perpendicular, then their slopes are opposite reciprocal (the product of their slopes is equal to -1)

$m_1*m_2=-1$

we have

$m_1=-\frac{7}{2}$

so

$m_2=\frac{2}{7}$

step 3

Find the equation of the line in point slope form

$y-y1=m(x-x1)$

we have

$m=\frac{2}{7}$

$point\ N(3,2)$

substitute

$y-2=\frac{2}{7}(x-3)$

step 4

Convert to slope intercept form

Isolate the variable y

$y-2=\frac{2}{7}x-\frac{6}{7}$

$y=\frac{2}{7}x-\frac{6}{7}+2$

$y=\frac{2}{7}x+\frac{8}{7}$

7 0

4 years ago