-- Carefully cut <em>each bar into 6 equal pieces</em>.
There are (5 x 6) = 30 pieces all together.
Each piece is 1/6 of a bar.
-- Each child gets 5 of the pieces.
That's the same as <em>5/6 of a whole bar</em>.
(6 children) x (5 pieces) = 30 pieces. It works out. yay !
Answer:
A. ¹/₁₄ lb
Step-by-step explanation:
¹/₁₆ lb sand goes with ⅞ lb compost.
For 1 lb compost, the mass of sand needed is:
1 lb compost × (¹/₁₆ lb sand)/(⅞ lb compost).
We must evaluate the fraction (¹/₁₆)/(⅞).
Invert the denominator and multiply
(¹/₁₆)/(⅞) = ¹/₁₆ × ⁸/₇ Cancel the 8s
= ½ × ⅐ Multiply numerators and denominators
= ¹/₁₄
For 1 lb of compost, the mass of sand needed is ¹/₁₄ lb.
Answer:
16
Step-by-step explanation:
9514 1404 393
Answer:
- arc BC = 60°
- m∠ADC = 60°
- m∠AEB = 105°
- m∠ADP = 45°
- m∠P = 60°
Step-by-step explanation:
The sum of arcs of a circle is 360°. The given conditions tell us arc BC ≅ arc AB, so the four arcs of the circle have ratios ...
CB : BA : AD : DC = 2 : 2 : 3 : 5
The sum of ratio units is 2+2+3+5 = 12, so each one stands for 360°/12 = 30°. Then the arc lengths are ...
arc BC = arc BA = 60° . . . . 2 ratio units each
arc AD = 90° . . . . . . . . . . . . 3 ratio units
arc DC = 150° . . . . . . . . . . . .5 ratio units
The inscribed angles are half the measure of the intercepted arcs:
∠ADC = (1/2) arc AC = 1/2(120°) = 60°
∠ADP = 1/2 arc AD = 1/2(90°) = 45°
The angles at E are half the sum of the measures of the intercepted arcs.
∠AEB = (arc AB + arc CD)/2 = (60° +150°)/2 = 105°
Angle P is half the difference of the intercepted arcs.
∠P = (arc BD -arc AD)/2 = (210° -90°)/2 = 120°/2 = 60°
__
In summary, ...
arc BC = 60°
m∠ADC = 60°
m∠AEB = 105°
m∠ADP = 45°
m∠P = 60°
Answer: 96 truckloads, 95 will be full, the last on will have 10 cars
Step-by-step explanation: 1150/12= 95.888> 95*12=1140, 1140+10=1150
