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DaniilM [7]
3 years ago
15

Can you help me please ​

Mathematics
1 answer:
MatroZZZ [7]3 years ago
4 0

This question is much easier than the last one. As we can see the yellow are is the same as the bottom area with the same shape. And the area of the 2 hemispheres adds together to a full circle area: 3^2*pi=9pi

Area of yellow region=(36-9pi)/2=18-9/2pi=3.862 and round this to the nearest tenth getting 3.9.

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KM bisects ÐJKL, mÐJKM = (2x + 5)°, and mÐMKL = (5x – 10)°. Find mÐJKM.
Gnom [1K]

Answer:

15 °

Step-by-step explanation:

An angular bisector can divide the angle in to 2 congruent angles.

According to the question, the angular bisector KM divides J K L angle into 2 congruent angles.

So,

< J K M = < M K L

2x + 5  = 5x - 10

Now let us find the value of x.

2x + 5  = 5x - 10

2x + 5 + 10 = 5x

15 = 5x - 2x

15 = 3x

You can divide both sides by 3.

5 = x

According to the question, we are asked to find the < J K M.

So,

< J K M = 2x + 5

            = 2 × 5 + 5

            = 10 + 5

            = 15

Hope this helps :-)

4 0
3 years ago
What is the next term of the arithmetic sequence? 7,11,15,19,7,11,15,19
natima [27]

Answer:

7

Step-by-step explanation:

4 times at an addition of 4, then a subtraction of 12

8 0
3 years ago
The rate of change of the downward velocity of a falling object is the acceleration of gravity (10 meters/sec 2) minus the accel
Alexus [3.1K]

Answer:

See below

Step-by-step explanation:

Write the initial value problem and the solution for the downward velocity for an object that is dropped (not thrown) from a great height.

if v(t) is the speed at time t after being dropped, v'(t) is the acceleration at time t, so the the initial value problem for the downward velocity is

v'(t) = 10 - 0.1v(t)

v(0) = 0 (since the object is dropped)

<em> The equation v'(t)+0.1v(t)=10 is an ordinary first order differential equation with an integrating factor </em>

\bf e^{\int {0.1dt}}=e^{0.1t}

so its general solution is  

\bf v(t)=Ce^{-0.1t}+100

To find C, we use the initial value v(0)=0, so C=-100

and the solution of the initial value problem is

\bf \boxed{v(t)=-100e^{-0.1t}+100}

what is the terminal velocity?

The terminal velocity is

\bf \lim_{t \to\infty}(-100e^{-0.1t}+100)=100\;mt/sec

How long before the object reaches 90% of terminal velocity?

90%  of terminal velocity = 90 m/sec

we look for a t such that

\bf -100e^{-0.1t}+100=90\rightarrow -100e^{-0.1t}=-10\rightarrow e^{-0.1t}=0.1\\-0.1t=ln(0.1)\rightarrow t=\frac{ln(0.1)}{-0.1}=23.026\;sec

How far has it fallen by that time?

The distance traveled after t seconds is given by

\bf \int_{0}^{t}v(t)dt

So, the distance traveled after 23.026 seconds is

\bf \int_{0}^{23.026}(-100e^{-0.1t}+100)dt=-100\int_{0}^{23.026}e^{-0.1t}dt+100\int_{0}^{23.026}dt=\\-100(-e^{-0.1*23.026}/0.1+1/0.1)+100*23.026=1,402.6\;mt

3 0
3 years ago
Using mental math find 4.623 x 1000. Please explain how you got your answer​
Makovka662 [10]

Answer:

4 623

Step-by-step explanation:

4.623 x 1000

When multiplying by a  positive power of 10, move the decimal by the number of zeros

Since we have 3 zeros, move the decimal 3 places to the right

4 623

3 0
4 years ago
Read 2 more answers
Whoever Is Really Good At Math Can You Help Me Out Please
Ratling [72]

Answer:

im not good at math

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
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