PLS HELP I RLY NEED IT
2 answers:
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Each of A, C, and D are rational, so presumably B is the answer here.
A is rational, since
, so 
.
C is also rational. If
, then 
. This would mean 
, and so 
.
D is rational by a similar argument. If
, then 
. So, 
, which means 
.
A is rational, since
C is also rational. If
D is rational by a similar argument. If
Hey there, hope I can help!
Assuming you know how to simplify this, I will not show the steps but can add them later on upon request
Lets use the quadratic formula now
Multiply the numbers 2 * 1 = 2
![\mathrm{Apply\:radical\:rule}: \sqrt[n]{ab}=\sqrt[n]{a}\sqrt[n]{b} \ \textgreater \ \sqrt{47}\sqrt{2^2}](https://tex.z-dn.net/?f=%5Cmathrm%7BApply%5C%3Aradical%5C%3Arule%7D%3A%20%5Csqrt%5Bn%5D%7Bab%7D%3D%5Csqrt%5Bn%5D%7Ba%7D%5Csqrt%5Bn%5D%7Bb%7D%20%5C%20%5Ctextgreater%20%5C%20%20%5Csqrt%7B47%7D%5Csqrt%7B2%5E2%7D%20)
![\mathrm{Apply\:radical\:rule}: \sqrt[n]{a^n}=a \ \textgreater \ \sqrt{2^2}=2 \ \textgreater \ 2\sqrt{47} \ \textgreater \ \frac{2+2\sqrt{47}}{2}](https://tex.z-dn.net/?f=%5Cmathrm%7BApply%5C%3Aradical%5C%3Arule%7D%3A%20%5Csqrt%5Bn%5D%7Ba%5En%7D%3Da%20%5C%20%5Ctextgreater%20%5C%20%20%5Csqrt%7B2%5E2%7D%3D2%20%5C%20%5Ctextgreater%20%5C%20%202%5Csqrt%7B47%7D%20%5C%20%5Ctextgreater%20%5C%20%20%5Cfrac%7B2%2B2%5Csqrt%7B47%7D%7D%7B2%7D)
Moving on, I will do the second part excluding the extra details that I had shown previously as from the first portion of the quadratic you can easily see what to do for the second part.
Therefore our final solutions are
Hope this helps!
Assuming you know how to simplify this, I will not show the steps but can add them later on upon request
Lets use the quadratic formula now
Multiply the numbers 2 * 1 = 2
Moving on, I will do the second part excluding the extra details that I had shown previously as from the first portion of the quadratic you can easily see what to do for the second part.
Therefore our final solutions are
Hope this helps!