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klemol [59]
2 years ago
12

I need help finding the sin cos tan​

Mathematics
1 answer:
jonny [76]2 years ago
3 0

Answer:

a. Sin (θ) = 3 / 5

b. Cos (θ) = 4 / 5

c. Tan (θ) = 3 / 4

Step-by-step explanation:

a. Sin (θ) = 6 / 10 = 3 / 5

b. Cos (θ) = 8 / 10 = 4 / 5

c. Tan (θ) = 6 / 8 = 3 / 4

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The length of a curve <em>C</em> parameterized by a vector function <em>r</em><em>(t)</em> = <em>x(t)</em> i + <em>y(t)</em> j over an interval <em>a</em> ≤ <em>t</em> ≤ <em>b</em> is

\displaystyle\int_C\mathrm ds = \int_a^b \sqrt{\left(\frac{\mathrm dx}{\mathrm dt}\right)^2+\left(\frac{\mathrm dy}{\mathrm dt}\right)^2} \,\mathrm dt

In this case, we have

<em>x(t)</em> = exp(<em>t</em> ) + exp(-<em>t</em> )   ==>   d<em>x</em>/d<em>t</em> = exp(<em>t</em> ) - exp(-<em>t</em> )

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=\displaystyle\int_0^2 \sqrt{e^{2t}+2+e^{-2t}} \,\mathrm dt

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