Answer:1
Step-by-step explanation:
Answer:
y=3
Step-by-step explanation:
y + 3 = -y + 9
y + y = 9 - 3
2*y = 6
y = 6/2
y = 3
Range is the y values or ouputs
domain is inputs or x vvalues
we can use any x value
but at a certain y value, w can't go below that
find thatminimum
find the vertex
for
ax^2+bx+c
the x value of the vertex is
-b/2a
plug that in to the equaiton to get the y value
-b/2a=-(-6)/(2*2)=6/4=3/2
plug that in
2(3/2)^2-6(3/2)-9
2(9/4)-9-9
9/2-18
4.5-18
-13.5
domain=all real numbers
range=from -13.5 to positive infinity
The wording of this question is a bit confusing... You can't write a sequence in sigma notation, but rather a series or sum. I think the question is asking you to write the sum of the sequence,
which would be
in sigma notation.
To do this, notice that the denominator in each term is a power of 2, starting with 
and ending with 
. So in sigma notation, this series is
Answer:
a(4) = 15/4
Step-by-step explanation:
Here we're told that the first term is a(1) = 30 and that the common factor r = 1/2.
Thus, the geometric sequence formula specific to this case is
a(n) = 30(1/:2)^(n-1).
What is the fourth term? Let n = 4,
a(4) = 30(1/2)^(4-1), or a(4) = 30(1/2)^(3), or a(4) = 30(1/8) = 30/8, or, in reduced form,
a(4) = 15/4.
