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Anastasy [175]
3 years ago
7

The product of a particular number and a second value, which is given by the sum of 8 and the original number, is 65. What is th

e number? A. x = 81 B. x = −13; x = 5 C. x = −9; x = 9 D. x = 5
Mathematics
1 answer:
Marina86 [1]3 years ago
8 0

Given:

The product of a particular number is 65.

Second value is given by the sum of 8 and the original number.

To find:

The unknown number.

Solution:

Let x be the unknown number.

Then, second number = x+8

The product of a particular number is 65.

x\times (x+8)=65

x^2+8x=65

x^2+8x-65=0

Splitting the middle term, we get

x^2+13x-5x-65=0

x(x+13)-5(x+13)=0

(x-5)(x+13)=0

Using zero product property, we get

x-5=0 and x+13=0

x=5 and x=-13

So, the unknown number is either 5 or -13.

Therefore, the correct option is B.

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3 years ago
Find the sum of the first 47 terms of the following series, to the nearest integer.
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Answer:

The sum of the first 47 terms of the series, 12, 16, 20, ... S₄₈ is 4,888

Step-by-step explanation:

The given series is;

12, 16, 20, ...,

Therefore, the first term of the series is, a = 12

The common difference of series is found as follows;

The difference between subsequent terms, 12 and 16 is  16 - 12 = 4

The difference between subsequent terms, 16, and 20 is  20 - 16 = 4

Therefore, the common difference, d = 4

The series is therefore an arithmetic projection, AP

The sum of the first 'n' terms of an AP, Sₙ, is given as follows;

S_n = \dfrac{n}{2} \cdot \left [2 \cdot a + (n - 1)\cdot d \right ]

(47/2)*(2*12+(47-1)*4)

The sum of the first 47 terms is therefore given as follows;

S_n = \dfrac{47}{2} \cdot \left [2 \times 12 + (47 - 1)\times 4 \right ] = 4,888

The sum of the first 47 terms of the series, 12, 16, 20, ... S₄₈ = 4,888

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3 years ago
Solve for y. <br> 6 = 2 (y+2)<br><br> y = ___
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0         1/3
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8 0
3 years ago
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