It would be 100. Hope it helps!
Answer:
Step-by-step explanation:
You are to make 5 assemblies.
Each assembly requires the use of 1 Type A bolt.
To make the 5 assemblies, you need 5 Type A bolts.
The container of bolts has a total of 60 bolts.
The focus - Type A bolts - is 20 out of this 60.
The probability of obtaining a Type A bolt at all, is 20/60, which is = 1/3
(A) What is the probability of taking the exact number of Type A bolts you need for your 5 assemblies, if you randomly take 10 bolts from the container?
- The exact number of Type A bolts you need for the 5 assemblies is 5
1/3 × 5/10 = 5/30 = 1/6 = 0.167
(B) What is the probability of taking/having less than 5 Type A bolts out of the randomly selected 10 bolts? The solution is to sum up the following:
1/3 × 4/10 = 0.133
1/3 × 3/10 = 0.1
1/3 × 2/10 = 0.067
1/3 × 1/10 = 0.033
1/3 × 0/10 = 0
TOTAL = 0.333
Answer:
ok the last option is for the middle one and I think the vocabulary one goes with the second one of the options sorry I dont know anything else
The answer is 3 bozo open ur eyes
The value of x is 15.
Solution:
Given ΔPQR 
ΔUTV.
<em>If two triangles are similar, then the corresponding parts are congruent.</em>
Do cross multiplication, we get
⇒ 14(x - 3) = 8(x + 6)
⇒ 14x - 42 = 8x + 48
Add 42 on both sides.
⇒ 14x = 8x + 90
Subtract 8x on both sides.
⇒ 6x = 90
Divide by 6 on both sides.
⇒ x = 15
The value of x is 15.
