Answer:
c) G(x) = (x + 1)**2
Step-by-step explanation:
A function left shift is x + shift and a right shift is x - shift.
That'd be true only if the value of "s" is the exact same one for both
namely if sec(s) = cos(s)
then solving for "s"
thus
![\bf sec(s)=cos(s)\qquad but\implies sec(\theta)=\cfrac{1}{cos(\theta)} \\\\\\ thus\cfrac{1}{cos(s)}=cos(s)\implies 1=cos^2(s)\implies \pm \sqrt{1}=cos(s) \\\\\\ \pm 1=cos(s)\impliedby \textit{now taking }cos^{-1}\textit{ to both sides} \\\\\\ cos^{-1}(\pm 1)=cos^{-1}[cos(s)]\implies cos^{-1}(\pm 1)=\measuredangle s](https://tex.z-dn.net/?f=%5Cbf%20sec%28s%29%3Dcos%28s%29%5Cqquad%20but%5Cimplies%20sec%28%5Ctheta%29%3D%5Ccfrac%7B1%7D%7Bcos%28%5Ctheta%29%7D%0A%5C%5C%5C%5C%5C%5C%0Athus%5Ccfrac%7B1%7D%7Bcos%28s%29%7D%3Dcos%28s%29%5Cimplies%201%3Dcos%5E2%28s%29%5Cimplies%20%5Cpm%20%5Csqrt%7B1%7D%3Dcos%28s%29%0A%5C%5C%5C%5C%5C%5C%0A%5Cpm%201%3Dcos%28s%29%5Cimpliedby%20%5Ctextit%7Bnow%20taking%20%7Dcos%5E%7B-1%7D%5Ctextit%7B%20to%20both%20sides%7D%0A%5C%5C%5C%5C%5C%5C%0Acos%5E%7B-1%7D%28%5Cpm%201%29%3Dcos%5E%7B-1%7D%5Bcos%28s%29%5D%5Cimplies%20cos%5E%7B-1%7D%28%5Cpm%201%29%3D%5Cmeasuredangle%20s)
Answer:
£0.60
Step-by-step explanation:
If each pack costs £1.59 and Nadia orders 15 packs,
then the total order before discount = 1.59 x 15 = £23.85
From the table given, we can see that for an order of £23.85 a 2.5% discount will be applied.
Divide £23.85 by 100 to get 1%: £23.85 ÷ 100 = £0.2385
Now multiply by 2.5 to get 2.5%: £0.2385 × 2.5 = £0.59625 = £0.60
Alternatively, the calculation in one expression is:
(1.59 × 15) × 0.025 = 0.59625
Please see below solution:
Let x = number of books that Bryan reads2x for amanda = Amanda 3x - 4 for Colin Amanda = 5/8(Bryan + Colin)2x = 5/8(x+3x-4)2x = 5/8(4x-4)
[16x = 5(4x-4)]816x = 20x - 20Subtract 20x from each side-4x =-20-4x/-4= -20/-4 divide -4 to eliminate the -4 in -4xx = 5
Therefore:
Bryan reads 5 books a month.
Since Amanda reads twice as many books a Bryan read so Amanda 10 books a month.
And Colin 11 books a month. 3(5) - 4 = 11
