-2. Because on the number line it goes -3 -2 -1 0 1 2 3 so if you count backwards from 2 it is -2
Domain: all real numbers
Range: y<0
Here we are given with a triangle with smaller triangles formed due to the altitude on AC. Given:
- AB = 6
- BC = 8
- <ABC = 90°
- BD ⊥ AC
- <ABD =
We have to find the value for sin
So, Let's start solving....
In ∆ADB and ∆ABC,
- <A = <A (common)
- <ABC = <ADB (90°)
So, ∆ADB ~ ∆ABC (By AA similarity)
The corresponding sides will be:
We know the value of AB and to find AC, we can use Pythagoras theoram that is:
AC = √6² + 8²
AC = 10
Coming back to the relation,
In ∆ADB, we have to find sin which is given by perpendicular/base:
Plugging the values of AD and AB,
Simplifying,
And this is our final answer.....
Carry On Learning !
Answer: i think it is 8 9 10
Step-by-step explanation: i dont know 100
Answer:
The solutions to equation 1 are x = 3, −1.5, and equation 2 has no solution.
Step-by-step explanation:
Rearranging the two equations, you get ...
- |4x -3| = 9 . . . . . has two solutions
- |2x +3| = -5 . . . . has no solutions (an absolute value cannot be negative)
The above-listed answer is the only one that matches these solution counts.
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Testing the above values of x reveals they are, indeed, solutions to Equation 1.