In a quadrilateral HELP, HE is congruent to LP. What other condition would prove that HELP is a parallelogram?
1 answer:
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Answer:
Graph has been shown in the attached file.
Step-by-step explanation:
We have been given the system of equations
Both the equation represents a straight lines. We can find the x and y intercepts of these lines to graph.
The intercept form of a line is given by
Here a is the x - intercept and b is the y-intercept.
Divide both sides of the equation (1) by 16
Hence, x-intercept = 4 and the point is (4,0)
y-intercept = 4 and the point is (0,4)
Similarly, for the second line
Divide both sides of the equation (2) by -6
x-intercept = -6 and the point is (-6,0)
y-intercept = -1 and the point is (0,-1)
We'll plot these points in the xy- plane and then join to get the graph of these lines.
