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fomenos
3 years ago
14

The sum of digits in a 2 digit number is 14. If you double the reversed number and add the result to the original number, the su

m would be 222. Find the original number.
PLS HELP ASAP!!!!!!!
Mathematics
2 answers:
Phantasy [73]3 years ago
8 0

Answer: The answer is 86

Step-by-step explanation: If you double the reversed number (68) you would get 136 then add 86 to that orignal sum and you get 222 voila. How i got the number was I did guess and check.

r-ruslan [8.4K]3 years ago
6 0

Answer:

86

Step-by-step explanation:

To figure this equation out I used a guess and check strategy. I looked at all combinations of digits that gave us a sum of 14. When I got to 86, and reversed the digits, I ended up getting 136. When I added 136 to 86 it was 222. We started with seven and seven, and then looked at eight and six and a six and eight. Eight in six was that right combination!

Hope this helps!!

Please tell me if I am incorrect I enjoy learning from my mistakes.

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The market and Stock J have the following probability distributions:
denis-greek [22]

Answer:

1) E(M) = 14*0.3 + 10*0.4 + 19*0.3 = 13.9 \%

2) E(J)= 22*0.3 + 4*0.4 + 12*0.3 = 11.8 \%

3) E(M^2) = 14^2*0.3 + 10^2*0.4 + 19^2*0.3 = 207.1

And the variance would be given by:

Var (M)= E(M^2) -[E(M)]^2 = 207.1 -(13.9^2)= 13.89

And the deviation would be:

Sd(M) = \sqrt{13.89}= 3.73

4) E(J^2) = 22^2*0.3 + 4^2*0.4 + 12^2*0.3 =194.8

And the variance would be given by:

Var (J)= E(J^2) -[E(J)]^2 = 194.8 -(11.8^2)= 55.56

And the deviation would be:

Sd(M) = \sqrt{55.56}= 7.45

Step-by-step explanation:

For this case we have the following distributions given:

Probability  M   J

0.3           14%  22%

0.4           10%    4%

0.3           19%    12%

Part 1

The expected value is given by this formula:

E(X)=\sum_{i=1}^n X_i P(X_i)

And replacing we got:

E(M) = 14*0.3 + 10*0.4 + 19*0.3 = 13.9 \%

Part 2

E(J)= 22*0.3 + 4*0.4 + 12*0.3 = 11.8 \%

Part 3

We can calculate the second moment first with the following formula:

E(M^2) = 14^2*0.3 + 10^2*0.4 + 19^2*0.3 = 207.1

And the variance would be given by:

Var (M)= E(M^2) -[E(M)]^2 = 207.1 -(13.9^2)= 13.89

And the deviation would be:

Sd(M) = \sqrt{13.89}= 3.73

Part 4

We can calculate the second moment first with the following formula:

E(J^2) = 22^2*0.3 + 4^2*0.4 + 12^2*0.3 =194.8

And the variance would be given by:

Var (J)= E(J^2) -[E(J)]^2 = 194.8 -(11.8^2)= 55.56

And the deviation would be:

Sd(M) = \sqrt{55.56}= 7.45

8 0
3 years ago
Hollis put a layer of boxes in the bottom of a container. Each box has a volume of 1 cubic foot. The base layer of boxes in the
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Answer:

288 ft³

Step-by-step explanation:

Given that

The volume of each box is 1 cubic foot

And, Hollies required 8 of these layers

Now based on the above information

We assume that the dimension of the base layer is 6 by 6

So, the volume of the container is

= Length × Width × Height

where,

Length = 6 ft

Width = 6 ft

And, Height = 8 ft

So,

= 6 ft × 6 ft × 8 ft

= 288 ft³

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