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Butoxors [25]
3 years ago
13

What is the focus of the parabola given by the equation y = x2 − 2x − 3?

Mathematics
1 answer:
erica [24]3 years ago
4 0
What is the focus of the parabola given by the equation y = x2 − 2x − 3?
y = x2 − 2x − 3
y = x2 − 2x − 3 -1 +1y = (x - 1)^2 - 4 h = 1 and  k = - 4 and  a = 1

Vertex (a, k) so it is  (1,-4)

Now focus is
(1, -4 + 1/4) = (1,-3 3/4)
or
(1,-3.75)
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What two numbers that can be added to -13 but also be multiply to 36
iragen [17]

Answer:

-9,-4

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Solve:
mash [69]

Answer:

1. Infinitely Many Solutions

2. Zero Solutions

3. One Solution ( x = 6 )

Step-by-step explanation:

1.

12x + 8 = 2( 6x + 4 )

12x + 8 = 12x + 8

2.

2( 2x + 1 ) = 4x + 3

4x + 2 = 4x + 3

2 = 3

3.

4( x + 1 ) = 3x + 10

4x + 4 = 3x + 10

x + 4 = 10

x = 6

Hopefully this helps!

Brainliest please?

8 0
3 years ago
What is the theoretical probability of rolling anything other than a two on a fair six sided die?
mrs_skeptik [129]

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5/6 probability

Step-by-step explanation:

6 0
3 years ago
Can someone help me solve this?
Sergio [31]

Answer:

m<c = 104°

m<d = 80°

Step-by-step explanation:

Recall: Opposite angles of a cyclic quadrilateral are supplementary. Therefore, their sum equals 180°. Thus:

m<c + 76° = 180°

m<c + 76° - 76° = 180° - 76° (subtraction property of equality)

m<c = 104°

m<d + 100° = 180°

m<d +100° - 100° = 180° - 100° (subtraction property of equality)

m<d = 80°

8 0
3 years ago
Please sketch graph of the function f(x) = |x+2|.
Burka [1]

Answer:

The absolute value can be graphed using the points around the vertex (-2, 0), (-4, 2), (-3, 1), (-1, 1), (0, 2).

Step-by-step explanation:

The find the x coordinate of the vertex, set the inside of the absolute value x + 2 equal to 0. In this case, x + 2 = 0.

x + 2 = 0

Subtract 2 from both sides of the equation.

x = -2

Replace the variable x with -2 in the expression.

y = |(-2) + 2|

The absolute value vertex is (-2, 0).

The domain of the expression is all real numbers except where the expression is undefined. In this case, there is no real number that makes the expression undefined.

For each x value, there is on y value. Select few z values from the domain. It would be more useful to select the values so that they are around the x value of the absolute value vertex.

Substitute the x value -4 into f(x) = |x+2|. In this case, the point is (-4,2).

y=2

Substitute the x value -3 into f(x) = |x+2|. In this case, the point is (-3,1).

y=1

Substitute the x value 0 into f(x) = |x+2|. In this case, the point is (0,2).

y=2

You can find the graph in the attachment.

6 0
3 years ago
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