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const2013 [10]
3 years ago
8

What inverse operation should be used to isolate the variable in the equation 10 × b = 90?

Mathematics
1 answer:
Pepsi [2]3 years ago
4 0
<h2>Division</h2><h3></h3><h3>10 x b = 90</h3><h3>is the same as</h3><h3>b x 10 = 90</h3><h3></h3><h3>divide both sides by 10</h3><h3>b x 10 ÷ 10 = b</h3><h3>90 ÷ 10 = 9</h3><h3></h3><h3>so</h3><h3>b = 9</h3>
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A sixth grade math student made this conjecture: every prime number can be expressed as the product of two prime numbers. Do you
iren [92.7K]

Answer:

No, I do not agree with the conjecture because 1 is not a prime number.

Step-by-step explanation:

A prime number is one that can be divided by 1 and itself only. Thus it can be expressed in 2 factors only, 1 and the number itself.

Examples are; 2, 3, 5, 13, 19 , 23 etc.

So, 2 = 1 x 2

      3 = 1 x 3

     23 = 1 x 23

Prime numbers must be expressed as the product of 1 and the number.

The conjecture that every prime number can be expressed as the product of two prime numbers is false. Because 1 is not a prime number, since it has no 2 factors.

5 0
3 years ago
The accompanying data came from a study of collusion in bidding within the construction industry. No. Bidders No. Contracts 2 6
viktelen [127]

Answer:

a)

The proportion of contracts involved at most five bidders is 0.667.

The proportion of contracts involved at least five bidders is 0.51.

b)

The  proportion of contracts involved  between five and 10 inclusive bidders is 0.5.

The  proportion of contracts involved  strictly between five and 10 bidders is 0.304.

Step-by-step explanation:

No. bidders    No. contracts     Relative frequency of contracts

2                         6                       6/102=0.0588

3                         20                     20/102=0.1961

4                         24                     24/102=0.2353

5                         18                       18/102=0.1765

6                         13                        13/102=0.1275

7                          7                          7/102=0.0686

8                          5                          5/102=0.049

9                          6                          6/102=0.0588

10                         2                           2/102=0.0196

11                          1                            1/102=0.0098

Total                  102

a)

We have to find proportion of contracts involved at most five bidders.

Proportion of at most 5= Relative frequency 2+ Relative frequency 3+ Relative frequency 4+ Relative frequency 5

Proportion of at most 5=0.0588+ 0.1961+0.2353+0.1765

Proportion of at most 5=0.6667

The proportion of contracts involved at most five bidders is 0.667.

proportion of at least five bidders= proportion≥5= 1- proportion less than 5

Proportion less than 5=0.0588+ 0.1961+0.2353=0.4902

proportion of at least five bidders=1-0.4902=0.5098

The proportion of contracts involved at least five bidders is 0.51

b)

We have to find proportion of contracts involved  between five and 10 inclusive bidders.

Proportion of contracts between five and 10 inclusive= Relative frequency 5+ Relative frequency 6+ Relative frequency 7+ Relative frequency 8+ Relative frequency 9+ Relative frequency 10

Proportion of between five and 10 inclusive=0.1765 +0.1275 +0.0686 +0.049 +0.0588 +0.0196

Proportion of between five and 10 inclusive=0.5

The  proportion of contracts involved  between five and 10 inclusive bidders is 0.5

We have to find proportion of contracts involved  strictly between five and 10 bidders.

Proportion of contracts strictly between five and 10=  Relative frequency 6+ Relative frequency 7+ Relative frequency 8+ Relative frequency 9

Proportion of strictly between five and 10=0.1275 +0.0686 +0.049 +0.0588

Proportion of strictly between five and 10=0.3039

The  proportion of contracts involved  strictly between five and 10 bidders is 0.304.

8 0
3 years ago
Solve this system of equations:<br><br> 5x + y = 7<br> 20x + 2 = y
xz_007 [3.2K]

Answer:

x = 1/5, y = 6

Step-by-step explanation:

5x + y = 7

y = 7 - 5x

Set equations equal to each other to eliminate y

7 - 5x = 20x + 2

7 = 25x + 2

5 = 25x

x = 1/5

y = 7 - 5(1/5)

y = 7 - 1

y = 6

7 0
3 years ago
In a seafood stew, Erin wants to use lobster, crab, and shrimp. She wants one part lobster, two parts crab, and three parts shri
alukav5142 [94]

Answer:

Answer: (B) 3

Step-by-step explanation:

20x + 15(2x) + 10(3x) = 40

20x + 30x + 30x = 40

80x = 40

x = 40/80

x = 1/2

Find the amount of lobster

Lobster = x = 1/2 pound

Find the amount of crab:

Crab = 2x = 2(1/2) = 1 pound

Find the amount of Shrimp:

Shrimp = 3x = 3(1/2) = 3/2 pounds

Find the total pounds of seafood:

Total = 1/2 + 1 + 3/2 = 3 pounds

Answer: (B) 3

6 0
3 years ago
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Answer:

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6 0
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