<span>80 ft^2
Looking at the figure, you can easily determine that it's made of two separate figures, a rectangle that's 2 feet by 16 feet, and a triangle that has sides of 16 feet, 10 feet, and 10 feet. The triangle can then be divided into two right triangles with a hypotenuse of 10 feet and one leg of 8 feet, so you can use the Pythagorean theorem to calculate the other leg (which is also the height of the large triangle mentioned above). That value is sqrt(10^2 - 8^2) = sqrt(100 - 64) = sqrt(36) = 6.
So we now know that the large 16,10,10 triangle has a base of 16 and a height of 6. So let's calculate the area of the entire figure.
A = 2*16 + 16*6/2
A = 32 + 16*3
A = 32 + 48
A = 80
So the area of the entire figure is 80 square feet.</span>
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Answer:
174 ft²
Step-by-step explanation:
Assuming you're interested in the area of the figure, you can compute it as the sum of the areas of the triangle and rectangle.
The unknown side of the triangle can be figured from the overall dimension of the rectangle and the two lengths that are not part of the triangle base:
6 ft + triangle base + 6 ft = 18 ft
triangle base = 18 ft - 12 ft = 6 ft
Then the area of the triangle is ...
A = 1/2bh = 1/2(6 ft)(4 ft) = 12 ft²
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Of course, the area of the rectangle is the product of its length and width:
A = LW = (18 ft)(9 ft) = 162 ft²
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The total area of the figure is the sum of these:
area = triangle area + rectangle area
area = 12 ft² +162 ft²
area = 174 ft²
Answer:
d.
Step-by-step explanation:
you would put 4 in the x places and 2 in the yplaces and then you would distribute 4^2 +3(2)/4(2)
16+6/2=22/8=2 3/4
(14,-1) is the answer to the question
