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ira [324]
3 years ago
14

Help me with this problem please

Mathematics
2 answers:
icang [17]3 years ago
6 0

Answer:

The answer is D.

Step-by-step explanation:

Vera_Pavlovna [14]3 years ago
4 0

Answer:

D

Step-by-step explanation:

the right answer is d when multiples by both sides

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An Airplane travels about 1500km in a straight line between Toronto and Winnipeg . However, the plane must climb to 10 000 m dur
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 it adds 227km more to the flight
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Raul is building a house. On day 1, he uses 3 bags of cement. On each of the following 3 days, he uses 3 times the number of bag
Ksivusya [100]
18bags 
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8 0
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3. Jim bought a new pair of glasses. The lenses had six sides. The lenses were in the shape of a A. hexagon. B. heptagon. C. qua
Vladimir [108]
Best Answer:<span>  </span><span>6 sides is a hexagon. 

the spoke of a wheel is like a radius. Circumference is equal to 2πr so r = 42/2π ≈ 6.69 inches, ans. D. 

that's it! ;)</span>
5 0
3 years ago
Variable y varies directly with variable x, and y = 5 when x = 8.
qaws [65]
Y = kx

Plug in what we know:

5 = k(8)

5 = 8k

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k = 0.625

Plug this back into the equation along with y = 15:

y = kx

15 = 0.625x

Divide 0.625 to both sides:

x = 24
4 0
3 years ago
Read 2 more answers
Factorise 2x^2 - 3x -2 &lt; 0
Galina-37 [17]
Step 1: Factor 2 x^{2} - 3x -2
1. <span> Multiply 2 by -2, which is -4.</span>
2. <span>Ask: Which two numbers add up to -3 and multiply to -4?
</span>3. <span>Answer: 1 and -4
</span>4. Rewrite -3x as the sum of x and -4x

2 x^{2} +x-4x-2\ \textless \ 0


Step 2: <span>Factor out common terms in the first two terms, then in the last two terms.

</span>x(2x+1)-2(2x+1)\ \textless \ 0
<span>
Step 3: </span>Factor out the common term 2x+1

(2x+1)(x-2)\ \textless \ 0

Step 4: Solve for x

1. Ask: When will (2x+1)(x-2) equal zero?
2. Answer: When 2x + 1 = 0 or x-2=0
3. <span>Solve each of the 2 equations above:

</span>x=- \frac{1}{2} ,2
<span>
Step 5: </span>From the values of x <span>above, we have these 3 intervals to test.
x = < -1/2
-1/2 < x < 2
x > 2

Step 6: P</span><span>ick a test point for each interval

</span>For the interval x\ \textless \ - \frac{1}{2} &#10;
Lets pick x=-1. Then, 2(-1) ^{2} -3 * -1 -2 \ \textless \  0
After simplifying, we get 3\ \textless \ 0, Which is false. 
Drop this interval.
<span>
For this interval - \frac{1}{2} \ \textless \ x\ \textless \ 2
Lets pick x=0. Then, 2* 0^{2} - 3 * 0-2\ \textless \ 0. After simplifying, we get -2\ \textless \ 0, which is true. Keep this <span>interval.

For the interval </span>x\ \textgreater \ 2

Lets pick x = 3. Then, 2 * 3  ^{2} -3*3-2\ \textless \ 0. After simplifying, we get 7\ \textless \ 0, Which is false. Drop this interval.

.Step 7: Therefore, 
- \frac{1}{2} \ \textless \ x\ \textless \ 2

Done! :)</span>
4 0
3 years ago
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