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likoan [24]
3 years ago
15

Convert 180lb to kg and round to nearest 10th

Mathematics
2 answers:
kiruha [24]3 years ago
3 0

81.6 is the correct answer


Verizon [17]3 years ago
3 0

Hi!

1lb = 0,45kg

180 lb = 180 * 0,45kg = 81,00

Hope this helps!

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If your teacher tells you to do questions 28 through 41 in your math book for homework, how many questions is that?
ANTONII [103]
41-28=13 questions, but you also have to do 41 and 28, so 15 questions
5 0
3 years ago
Read 2 more answers
Which of the following expressions is written in simplest form
nadya68 [22]

Answer: I x^2 y^3 z

Step-by-step explanation:

This is the one most simplified. I’ll tell you why the others are incorrect.

F) 3^5 x^2 can be simplified. 3^5= 243. The simplified answer would be 243 x^2

G) (5y)^3= 125y^3

H) a^0 b (^0= 1 always) -> ab

Hope this helps!

3 0
3 years ago
Help me please and thank you ​
goldenfox [79]
I believe the answer is 78.54 , D
4 0
3 years ago
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Sea un cuadrado de 2 pulgadas de lado uniendo los puntos medios se obtiene otro cuadrado inscrito en el anterior si repetimos es
Ne4ueva [31]

Answer:

1) La serie geométrica formada es

4, 2, 1,..., ∞

2) La suma al infinito de las áreas de los cuadrados es 8 in.²

Step-by-step explanation:

1) El área del primer cuadrado, a₁ = 2² = 4 pulgadas²

El área del siguiente cuadrado, a₂ = (√ (1² + 1²)) ² = (√2) ² = 2 pulg²

El área del siguiente cuadrado, a₃ = ((√ (2) / 2) ² + (√ (2) / 2) ²) = 1 pulg²

Por lo tanto, la razón común, r = a₂ / a₁ = 2/4 = a₃ / a₂ = 1/2

Las áreas de los cuadrados progresivos forman una progresión geométrica como sigue;

4, 4×(1/2), 4 ×(1/2)²,...,4×(1/2)^{\infty}

De donde obtenemos la serie geométrica formada de la siguiente manera;

4, 2, 1,..., ∞

2) La suma de 'n' términos de una progresión geométrica hasta el infinito para -1 <r <1 se da como sigue;

S_{\infty} = \dfrac{a}{1 - r}

Por lo tanto, la suma de las áreas de los cuadrados hasta el infinito se obtiene sustituyendo los valores de 'a' y 'r' en la ecuación anterior de la siguiente manera;

La \ suma \ al \ infinito \ del \ cuadrado \ S_{\infty}  = \dfrac{4 \ in.^2}{1 - \dfrac{1}{2} } = \dfrac{4 \ in.^2}{\left(\dfrac{1}{2} \right)} = 2 \times 4 \ in.^2= 8 \ in.^2

La suma al infinito de las áreas de los cuadrados, S_{\infty} = 8 in.²

7 0
2 years ago
The regular nonagon has rotational symmetry of which angle measures
Margarita [4]
Rotational symmetry = 360 / # sides
rotational symmetry = 360 / 9
rotational symmetry = 40 degrees


6 0
3 years ago
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