Answer:
y=Ae^(1.25t)
Step-by-step explanation:
From the expression y=Ae^kt
After two days of the experiment, y = 49 million, t=2
After four days of the experiment, y= 600.25 million, t=4
A is the amount of bacteria present at time zero and t is the time after the experiment (in days)
At t=2 and y =49
49=Ae^2k…………….. (1)
At t=4 and y = 600.25
600.25=Ae^4k………… (2)
Divide equation (2) by equation (1)
600.25/49=(Ae^4k)/(Ae^2k )
12.25=e^2k
Take natural log of both sides
ln(12.25) =2k
2.505 =2k
k=1.25
The exponential equation that models this situation is y=Ae^(1.25t)
Answer:
1/72
Step-by-step explanation:
2^-3 = 1/2^3 = 1/8
3^-2 = 1/3^2 = 1/9
1/8 x 1/9 = 1/72
Hello!
Ill make this quick. The Fire house is in the third quadrant.
Hopefully this helps :)
Answer:
the answer is d. work is pictured
3/4=0.75
5/10=0.5
4/9≈0.44
2/6≈0.33
2/8=0.25
4/6≈0.67
