Answer:
I think is the same formula area .A triangle is half as big as the rectangle that surrounds it, which is why the area of a triangle is one-half base times height.
Step-by-step explanation:
The area of a rectangle is given by the relation length* width. The area of a triangle is given by the relation (1/2)*base* height. Now we know that the two have the same area equal to 150 cm^2. Also, when placed on the same level the tip of the triangle touches the upper edge of the rectangle.
The correct answer is A. D
That is because D has a horizontal line of symmetry, as can be seen on it.
Answer:
Required equation is y - 36 = (24 - 36)/(2 - 1) (x - 1)
y - 36 = -12(x - 1)
y - 36 = -12x + 12
12x + y = 12 + 36
12x + y = 48
Step-by-step explanation:
Answer:
Step-by-step explanation:
In a dilatation for find the new coordinates we have to multiply the initial value for the the scale factor
A’(-3, 12)
B’(9,6)
C’(-9,-3)
so the general rule is:
(x,y) -> (3x, 3y)
Answer: 4.5 miles
Explanation:
When you draw the situation you find two triangles.
1) Triangle to the east of the helicopter
a) elevation angle from the high school to the helicopter = depression angle from the helicopter to the high school = 20°
b) hypotensue = distance between the high school and the helicopter
c) opposite-leg to angle 20° = heigth of the helicopter
d) adyacent leg to the angle 20° = horizontal distance between the high school and the helicopter = x
2) triangle to the west of the helicopter
a) elevation angle from elementary school to the helicopter = depression angle from helicopter to the elementary school = 62°
b) distance between the helicopter and the elementary school = hypotenuse
c) opposite-leg to angle 62° = height of the helicopter
d) adyacent-leg to angle 62° = horizontal distance between the elementary school and the helicopter = 5 - x
3) tangent ratios
a) triangle with the helicpoter and the high school
tan 20° = Height / x ⇒ height = x tan 20°
b) triangle with the helicopter and the elementary school
tan 62° = Height / (5 - x) ⇒ height = (5 - x) tan 62°
c) equal the height from both triangles:
x tan 20° = (5 - x) tan 62°
x tan 20° = 5 tan 62° - x tan 62°
x tan 20° + x tan 62° = 5 tan 62°
x (tan 20° + tan 62°) = 5 tan 62°
⇒ x = 5 tant 62° / ( tan 20° + tan 62°)
⇒ x = 4,19 miles
=> height = x tan 20° = 4,19 tan 20° = 1,525 miles
4) Calculate the hypotenuse of this triangle:
hipotenuese ² = x² + height ² = (4.19)² + (1.525)² = 19.88 miles²
hipotenuse = 4.46 miles
Rounded to the nearest tenth = 4.5 miles
That is the distance between the helicopter and the high school.
