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xxTIMURxx [149]
3 years ago
13

How can I simplify/rewrite the 1st(top) equation into the 2nd(Botton),please show a step by step solution.​

Mathematics
1 answer:
Vaselesa [24]3 years ago
4 0

Answer:

see below

Step-by-step explanation:

-2(4 - \frac{x}{2} )^{5} + C

Think of the above as:

  -\frac{2}{1} * (\frac{8}{2} - \frac{x}{2} )^{5} + C

= -\frac{2}{1} * \frac{(8 - x)^{5}}{2^{5}}  + C

= -\frac{2}{1} * \frac{(8 - x)^{5}}{32}  + C

= -\frac{1}{1} * \frac{(8 - x)^{5}}{16}  + C

=   \frac{-1(8 - x)^{5}}{16}  + C

=   \frac{(-8 + x)^{5}}{16}  + C

Can flip it around to be...

\frac{(x - 8)^{5}}{16}  + C

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How do you solve <br>|3x|=18
Oduvanchick [21]

We can get two different equations from this:

3x = 18

and

3x = -18

So:

x = 6, x = -6

x = {6, -6}

6 0
3 years ago
Read 2 more answers
The hypotenuse of a right triangle is 45 inches,which one of the sides being 18 inches. Find the midding side length. Round to t
bagirrra123 [75]

Answer:

The length of the missing side is 41.24 inches

Step-by-step explanation:

* Lets talk about the Pythagoras theorem

- It used in the right angle triangle

- The hypotenuse is the opposite side to the right angle and it's the

  longest side in the triangle

- The two other sides in the right angle triangle are the legs of

 the right angle

- If the length of the hypotenuse is c units and the lengths of the

 two legs of the right angle area a and b

∴ a² + b² = c² ⇒ c = √(a² + b²)

* Now lets solve the problem

∵ The length of the hypotenuse = 45 inches

∵ The length of one legs of the right angle = 18 inches

- Lets use the Pythagoras theorem

∴ c² = a² + b²

∴ 45² = 18² + b² ⇒ subtract 18² from both sides

∴ b² = 45² - 18² = 2025 - 324 = 1701 ⇒ take square root for both sides

∴ b = √1701 = 41.24 inches

8 0
3 years ago
Read 2 more answers
There are three clubs at Redwood High School: Debate, Student council, and Key club. There are 1000 students in the school. And
hram777 [196]

Answer:

The number of students in the key club is 490

Step-by-step explanation:

The given parameters are;

The number of student in the school = 1000

The total number of student in the debate club = 310

The total number of student in the student council = 650

The total number of student who are in debate and student council = 170

The total number of student who are in both debate and the key club = 150

The total number of student who are in both student council and the key club = 180

The number of students who are in all three clubs = 50

Therefore, we have;

Let A represent the number of students in the debate club

Let B represent the number of students in the student council

Let C represent the number of students in the key club

We have;

n(A∪B∪C) = n(A) + n(B) + n(C) -  n(A∩B) - n(B∩C) - n(C∩A) + n(A∩B∩C)

Where;

n(A∪B∪C) = 1000

n(A) = 310

n(B) = 650

n(A∩B) = 170

n(B∩C) = 180

n(C∩A) = 150

n(A∩B∩C) = 50

Therefore;

n(C) = n(A∪B∪C) - (n(A) + n(B) -  n(A∩B) - n(B∩C) - n(C∩A) + n(A∩B∩C))

Substituting the values gives;

n(C) = 1000 - (310 + 650 -  170 - 180 - 150 + 50) = 490

The number of students in the key club, n(C) = 490.

5 0
3 years ago
What is the ratio of 20 praise and 2000 rupees<br>​
AnnZ [28]
1:100 because 20 divide by 20=1 and 2000 divide by 20 =100
8 0
4 years ago
Read 2 more answers
Someone please help me ASAP
Minchanka [31]

Answer:

There is 1 boy per 2 girls

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
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