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3 years ago

What addition sentence does this show?

Mathematics

1 answer:

goldfiish [28.3K]3 years ago

7 0

The answer is C because when adding two negatives it equals a positive

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allochka39001 [22]

Answer:

Step-by-step explanation:

It's in the same order, from broker 1 down to broker 5. Straight up

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3 years ago

I need help with this, can anybody help me? thank you, have. a great day!

Ganezh [65]

Answer:a

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

An article reported on the results of an experiment in which half of the individuals in a group of 66 postmenopausal overweight

kicyunya [14]

Answer:

We conclude that the true average weight loss for the vegan diet exceeds that for the control diet by more than 1 kg.

Step-by-step explanation:

We are given that an article reported on the results of an experiment in which half of the individuals in a group of 66 postmenopausal overweight women were randomly assigned to a particular vegan diet, and the other half received a diet based on National Cholesterol Education Program guidelines.

The sample mean decrease in body weight for those on the vegan diet was 6 kg, and the sample SD was 3.2, whereas, for those on the control diet, the sample mean weight loss and standard deviation were 3.8 and 2.4, respectively.

Let = true average weight loss for the vegan diet.

$\mu_2$ = true average weight loss for the control diet.

So, Null Hypothesis, : 1 kg {means that the true average weight loss for the vegan diet exceeds that for the control diet by less than or equal to 1 kg}

Alternate Hypothesis, : > 1 kg {means that the true average weight loss for the vegan diet exceeds that for the control diet by more than 1 kg}

The test statistics that will be used here is Two-sample t-test statistics because we don't know about population standard deviations;

T.S. = $\frac{(\bar X_1-\barX_2)-(\mu_1-\mu_2)}{s_p \times \sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }$ ~ $t__n_1_+_n_2_-_2$

where, = sample mean weight loss for the vegan diet = 6 kg

= sample mean weight loss for the control diet = 3.8 kg

= sample standard deviation weight loss for the vegan diet = 3.2 kg

= sample standard deviation weight loss for the control diet = 2.4 kg

$n_1$ = sample of vegan diet women = 33

$n_2$ = sample of control diet women = 33

Also, $s_p=\sqrt{\frac{(n_1-1)\times s_1^{2}+(n_2-1)\times s_2^{2} }{n_1+n_2-2} }$ = $\sqrt{\frac{(33-1)\times 3.2^{2}+(33-1)\times 2.4^{2} }{33+33-2} }$ = 2.83

So, the test statistics = $\frac{(6-3.8)-(1)}{2.83 \times \sqrt{\frac{1}{33}+\frac{1}{33} } }$ ~ $t_6_4$

= 1.722

The value of t-test statistics is 1.722.

Also, the P-value of the test statistics is given by;

P-value = P( $t_6_4$ > 1.722) = 0.0461 or 4.61%

Since the P-value of our test statistics is less than the level of significance as 0.0461 < 0.05, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region.

Therefore, we conclude that the true average weight loss for the vegan diet exceeds that for the control diet by more than 1 kg.

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3 years ago

The moon is a 17% waxing crescent phase, located at a 50 degree angle from the sun. how many hours after sunrise with the moon r

Rzqust [24]

2864.788976 / 17% = 168.5169986

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4 years ago

Please answer the question in the picture.

Anon25 [30]

The answer is. A! All you do is times the numbers in A by every time table too find the correct answer.

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4 years ago