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3 years ago

Help please. Angle SPR and angle RPQ are complementary. Find the measure of angle RPQ.

Mathematics

2 answers:

Over [174]3 years ago

3 0

Answer:

53 degrees

Step-by-step explanation:

Complimentary angles are angles whose sum equals 90 degrees.

90-37 = 53

hichkok12 [17]3 years ago

3 0

Answer:

m∠RPQ = 53°

53 degrees

Step-by-step explanation:

When two angles are complementary angles, it means they add up to 90 degrees (Ex: a 10° angle and 80° angle would be complementary).

Therefore, if ∠SPR and ∠RPQ are complementary, then

m∠SPR + m∠RPQ = 90°

since you are given that m∠SPR = 37°, you can plug that in for m∠SPR to find m∠RPQ:

m∠SPR + m∠RPQ = 90°

37° + m∠RPQ = 90°

m∠RPQ = 90° - 37°

m∠RPQ = 53°

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Solve each quadratic equation by completing the square. Give exact answers--no decimals.

denis-greek [22]

Answer:

$x_1 = \frac{3}{2} + \frac{1}{2}(\sqrt{47})i\\\\x_2 = \frac{3}{2} - \frac{1}{2}(\sqrt{47})i\\\\$

Step-by-step explanation:

In this problem we have the equation of the following quadratic equation and we want to solve it using the method of square completion:

$x ^ 2 -3x +14 = 0$

The steps are shown below:

For any equation of the form: $ax ^ 2 + bx + c = 0$

1. If the coefficient a is different from 1, then take a as a common factor.

In this case $a = 1$ .

Then we go directly to step 2

2. Take the coefficient b that accompanies the variable x. In this case the coefficient is -3. Then, divide by 2 and the result squared it.

We have:

$\frac{-3}{2} = -\frac{3}{2}\\\\(-\frac{3}{2}) ^ 2 = (\frac{9}{4})$

3. Add the term obtained in the previous step on both sides of equality:

$x ^ 2 -3x + (\frac{9}{4}) = -14 + (\frac{9}{4})$

4. Factor the resulting expression, and you will get:

$(x -\frac{3}{2}) ^ 2 = -(\frac{47}{4})$

Now solve the equation:

Note that the term $(x -\frac{3}{2}) ^ 2$ is always > 0 therefore it can not be equal to $-(\frac{47}{4})$

The equation has no solution in real numbers.

In the same way we can find the complex roots:

$(x -\frac{3}{2}) ^ 2 = -(\frac{47}{4})\\\\x -\frac{3}{2} = \±\sqrt{-(\frac{47}{4})}\\\\x = \frac{3}{2} \±\frac{1}{2}\sqrt{-47}\\\\x = \frac{3}{2} \±\frac{1}{2}(\sqrt{47})i\\\\x_1 = \frac{3}{2} + \frac{1}{2}(\sqrt{47})i\\\\x_2 = \frac{3}{2} - \frac{1}{2}(\sqrt{47})i\\\\$