Let us assume number of toppings = n
Total weight of sundae = s
Quantity of Ice cream = 2 kilograms.
We need to discribe the total weight of the special sundae in kilograms by an inequality.
The sundae contains ice cream and number of toppings.
So the total weight of the sundae will be greater than the total weight of ice cream and number of toppings, because there would be some weight of the packing.
Therefore,
The total weight of the sundae > total weight of ice cream + weight of toppings.
s > 2 + n.
Where, s is the total weight of the sundae and n is the weight of toppings. I hope this was helpful!. :)
According to the context of the sentence, for it to be complete and make sense we must add the missing word as it follows:
- Según el <u>cártel</u>, la función comienza a las 8 de la noche.
- <em>Translation</em>: According to the <u>poster</u>, the show begins at 8 at night.
A poster refers to a sheet that presents some type of information that is intended to be disseminated.
- It captures the attention of the viewer, forcing him to perceive the message, his function to announce an event and disseminate information.
- In the sentence, the <em>''</em><em>cártel</em><em>''</em> complies with informing the spectators of the start time of the show.
Therefore, we can conclude that the correct missing word in the sentence is<em> cártel (post)</em>, which is planned to give certain information about the show.
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I agree because when u have confidence , ur more strong
The calculated pH of the solutions are given below:
- The pH of the solution after 14.0 ml of base is added to it is calculated as 1.45.
- The pH of the solution after 19.8 ml of base is added to it is calculated as 3.0
- The pH of the solution after 20.0 ml of base is added to it is calculated as 7.
<h3>What is pH?</h3>
This is the level of acidity or alkalinity of an aqueous solution. The pH of a substances tells if its an acid, base or neutral.
HBr and NaOH while in water would dissociate and they would become H+ and OH- respectively.
Mol of HBr = Mol * Vol
= 0.200 * 20mL
= 4 mmol
A. Moles of NaOH added
= 0.2 X 14
= 2.8 mmol
Moles of H+ that did not react
= 4 - 2.8
= 1.2 mmol
1.2/1000 = 0.0012 moles
Total volume = 20 + 14
= 34 mL to litres
= 0.034 L
Molarity of H+ = 0.0012 / 0.034L
= 0.035 M
-log[0.035] = 1.45
The pH of the solution is 1.45
B. NaOH added = 19.8 * 0.2 =
3.96 mmoles
The unreacted solution
= 4.0 - 3.96
= 0.04 mmol
0.04/1000 = 0.00004 moles
Total volume = 20 + 19.8
= 39.8mL
Converted to litres = 0.0398L
Molarity = 0.00004 / 0.0398L
= 0.001
-log(0.001) = 3.0
The ph Is therefore 3.0
C. Moles of NaOH added = 0.2*20mL = 4mmol
All the H+ are going to be consumed here. This would result into a neutral solution pH = 7
<u>Complete question:</u>
20.0 mL sample of 0.200 M HBr solution is titrated with 0.200 M NaOH solution. Calculate the PH of the solution after the following volumes of base have been added.
A. 14.0 mL
B. 19.8 mL
C. 20.0 mL
Read more on pH here; brainly.com/question/22390063
Answer:
10³
Explanation:
if u multiply 10 3times by itself u get 1000
10×10×10=1000