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fomenos
3 years ago
8

Which system of equations shows a solution of (0.5, -1)? Need answers asap plzzz

Mathematics
1 answer:
irina1246 [14]3 years ago
3 0

Answer:

The first graph

Step-by-step explanation:

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From 100 yards away, a marksman hit 16/23 of the targets last year. Rewrite the fraction as a percentage.
Elis [28]

Answer:69.565217391304%

Step-by-step explanation:  

vous devrez peut-être arrondir cela

5 0
3 years ago
Rewrite 3/2 : 1/4 as a unite rate
finlep [7]

Answer:

6 : 1

Step-by-step explanation:

A unit rate has to be "a number to 1" or "x:1". Here we have a number to 1/4. Multiply both numbers by 4 so the 1/4 becomes 1.

3/2 * 4 = 12/2 = 6

1/4 * 4 = 1

3/2 : 1/4 is the same as 6 : 1

6 0
4 years ago
Read 2 more answers
Help me plz assap plz
photoshop1234 [79]

The answer to the question is b

4 0
3 years ago
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If f(x) = x2, and g(x) = x – 1, then <br> g(f(x))= x^2 + ?
BARSIC [14]

-1 is the answer

Step-by-step explanation:

g(f(x))=g(x^2)

=x^2+(-1)

8 0
3 years ago
I rlly need help with this :(
kobusy [5.1K]

Using the normal distribution, it is found that:

a) The pilot is at the 72th percentile.

b) 19.13% of pilots are unable to fly.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean \mu and standard deviation \sigma is given by:

Z = \frac{X - \mu}{\sigma}

  • The z-score measures how many standard deviations the measure is above or below the mean.
  • Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

The mean and the standard deviation are given, respectively, by:

\mu = 72.6, \sigma = 2.7.

Item a:

The percentile is the <u>p-value of Z when X = 74.2</u>, hence:

Z = \frac{X - \mu}{\sigma}

Z = \frac{74.2 - 72.6}{2.7}

Z = 0.59

Z = 0.59 has a p-value of 0.7224.

72th percentile.

Item b:

The proportion that is able to fly is the <u>p-value of Z when X = 78 subtracted by the p-value of Z when X = 70</u>, hence:

X = 78:

Z = \frac{X - \mu}{\sigma}

Z = \frac{78 - 72.6}{2.7}

Z = 2

Z = 2 has a p-value of 0.9772.

X = 70:

Z = \frac{X - \mu}{\sigma}

Z = \frac{70 - 72.6}{2.7}

Z = -0.96

Z = -0.96 has a p-value of 0.1685.

0.9772 - 0.1685 = 0.8087 = 80.87%.

Hence the percentage that is unable to fly is:

100 - 80.87 = 19.13%.

More can be learned about the normal distribution at brainly.com/question/4079902

#SPJ1

3 0
2 years ago
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