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schepotkina [342]
3 years ago
5

Can someone please help me complete the factoring of the polynomial

Mathematics
1 answer:
gavmur [86]3 years ago
4 0
(3-5y) is the factored part
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What is 1.13 (where the three is repeating) written as a fraction? Someone pleaseee help!
Bess [88]

Answer:

13/90

Step-by-step explanation:

The decimal that you wrote is mixed non terminal decimal. Which means all the number don't repeat themselves.

The denominator of a non terminating decimal is always 9 even though it depends on the type of the decimal, whether it is simple or mixed

The denominator of the given decimal is 90. The denominator is 2 digit number since the given decimal is also 2 digit decimal even though it is under repeating bars.

And the numerator is 10, 13-3.

We subtract 3 since it is the one repeating itself.

Hope it helps ;) ❤❤❤

3 0
4 years ago
Find the constant of proportional (r) in the equation y = rx​
RUDIKE [14]

Answer:

Constant of proportionality,  

Step-by-step explanation:

Constant of proportionality states that the constant value of the ratio of two proportional quantities x and y,

it is written in the form of y = kx, where k is the constant of proportionality.

Given the equation:                         .....[1]

where r is the constant of proportionality.

From the table we consider

x = 14 and y = 1.4

Substitute these given values in [1] to solve for r;

Divide both sides by 14 we get;

therefore, the Constant of proportionality,  

4 0
3 years ago
Solve the equation.<br><br> x2 = 160
Airida [17]
Divide both side by 2 ad you get x=80
6 0
3 years ago
Which of the following expressions is equal to 5 to the 6th power divided by 5 to the 5th power
Jobisdone [24]
Asey

remember
\frac{x^m}{x^n}=x^{m-n}
so

\frac{5^6}{5^5}=5^{6-5}=5^1=5

8 0
3 years ago
Read 2 more answers
Classify ABC by its sides. Then determine whether it is a right triangle.
m_a_m_a [10]

Answer:

∴Given Δ ABC is not a right-angle triangle

a= AB = √45 = 3√5

b = BC = 12

c = AC = √45 = 3√5

Step-by-step explanation:

Given vertices are A(3,3) and B(6,9)

            AB = \sqrt{x_{2}-x_{1} )^{2} +(y_{2}-y_{1} )^{2}  }

            AB = \sqrt{(9-3)^{2}+(6-3)^{2}  } = \sqrt{6^{2}+3^{2}  } =\sqrt{45}

Given vertices are  B(6,9) and C( 6,-3)

       B C = \sqrt{x_{2}-x_{1} )^{2} +(y_{2}-y_{1} )^{2}  }

             =  \sqrt{(-3-9)^{2}+(6-6)^{2}  } =\sqrt{12^{2} } = 12

    BC = 12

Given vertices are  A(3,3) and C( 6,-3)

 AC = \sqrt{(6-3)^{2}+(-3-3)^{2}  } = \sqrt{9+36} = \sqrt{45}

AC² = AB²+BC²

45  = 45+144

 45  ≠ 189

∴Given Δ ABC is not a right angle triangle

 

5 0
3 years ago
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